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Nuetrik [128]
3 years ago
9

You have two LANs connected via a router. Network 1 has a DHCP server with a single Ethernet interface. Network 2 does not have

a DHCP server. You want the h​osts on Network 2 to be able to get IP addresses from the DHCP server on Network 1. What should you configure?
Computers and Technology
2 answers:
earnstyle [38]3 years ago
5 0

Answer:

You will Configure a LAN with DHCP and VLANs.

Explanation:

Routers generally support clients on both physical Local Area Networks ork (LANs) and Virtual Local Area Networks (VLANs). The routers can use the Dynamic Host Configuration Protocol (DHCP) to enable automatic assignment of IP configurations for nodes on these networks i.e the network 2.

The Dynamic Host Configuration Protocol (DHCP), uses a client/server model for address allocation. It means it automatically assigns an IP address to each client.

Virtual Local Area Networks (VLANs) enable networks to be segmented or broken and formed into logical groups of users, regardless of the user's physical location or Local Area Network connection.

slava [35]3 years ago
4 0

Answer:

The best thing to configure is the DHCP Server.

Explanation:

DHCP stand for Dynamic Hosting Configuration Protocol which is a sever used to automatically assign IP addresses, default gateways, domain names, etc to various users connected on a network. From the question above, since Network 1 has already configured DHCP server which provides IP addressing to its hosts, and Network 1 and Network 2 are connected to the same router directly, then then there is need to configure  DHCP server for Network 2 users for IP addressing . DHCP server is basically flexible and robust enough to do hots IP configurations which it was build for other than the router which may likely result into delay in packet delivery and communication with connected networks.

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Mumz [18]

Answer:

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3 0
2 years ago
How to get out of compatibility mode in word?
fomenos
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5 0
3 years ago
HELP ME PLEASE !!!!!!!!!!
Snezhnost [94]

Answer:

the last one

Explanation:

8 0
3 years ago
A computer retail store has 15 personal computers in stock. A buyer wants to purchase 3 of them. Unknown to either the retail st
Dima020 [189]

Answer:

a. 1365 ways

b. Probability = 0.4096

c. Probability = 0.5904

Explanation:

Given

PCs = 15

Purchase = 3

Solving (a): Ways to select 4 computers out of 15, we make use of Combination formula as follows;

^nC_r = \frac{n!}{(n-r)!r!}

Where n = 15\ and\ r = 4

^{15}C_4 = \frac{15!}{(15-4)!4!}

^{15}C_4 = \frac{15!}{11!4!}

^{15}C_4 = \frac{15 * 14 * 13 * 12 * 11!}{11! * 4 * 3 * 2 * 1}

^{15}C_4 = \frac{15 * 14 * 13 * 12}{4 * 3 * 2 * 1}

^{15}C_4 = \frac{32760}{24}

^{15}C_4 = 1365

<em>Hence, there are 1365 ways </em>

Solving (b): The probability that exactly 1 will be defective (from the selected 4)

First, we calculate the probability of a PC being defective (p) and probability of a PC not being defective (q)

<em>From the given parameters; 3 out of 15 is detective;</em>

So;

p = 3/15

p = 0.2

q = 1 - p

q = 1 - 0.2

q = 0.8

Solving further using binomial;

(p + q)^n = p^n + ^nC_1p^{n-1}q + ^nC_2p^{n-2}q^2 + .....+q^n

Where n = 4

For the probability that exactly 1 out of 4 will be defective, we make use of

Probability =  ^nC_3pq^3

Substitute 4 for n, 0.2 for p and 0.8 for q

Probability =  ^4C_3 * 0.2 * 0.8^3

Probability =  \frac{4!}{3!1!} * 0.2 * 0.8^3

Probability = 4 * 0.2 * 0.8^3

Probability = 0.4096

Solving (c): Probability that at least one is defective;

In probability, opposite probability sums to 1;

Hence;

<em>Probability that at least one is defective + Probability that at none is defective = 1</em>

Probability that none is defective is calculated as thus;

Probability =  q^n

Substitute 4 for n and 0.8 for q

Probability =  0.8^4

Probability = 0.4096

Substitute 0.4096 for Probability that at none is defective

Probability that at least one is defective + 0.4096= 1

Collect Like Terms

Probability = 1 - 0.4096

Probability = 0.5904

8 0
3 years ago
Your computer has two basic types of software: system software and ________ software.
Elan Coil [88]
Hi!

Our computers will have system software and application software. Application software would be something like a game or just any general purpose app you've downloaded.

Hopefully, this helps! =)
5 0
3 years ago
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