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Fudgin [204]
3 years ago
8

What is the solution of log(2+4) = log(14-3)?

Mathematics
1 answer:
MrMuchimi3 years ago
6 0

Answer:

To simplify: log10(2+4) = log10(14-3) your answer: 45

To expand: Click on the picture to get full view. Thought it would be easier to understand this way instead of me writing what I got on paper out on brainly. The answer for this is also: 45

Hope this helps! If so please mark brainliest and rate/heart if it did so it will help out my account!

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A gift box is a rectangular prism. The box measures 12 in by 14 in by 7 in.
Olin [163]

Answer:

1176

Step-by-step explanation:

12 times 7 equals 84.84 times 14 is 1176

4 0
3 years ago
Read 2 more answers
Solve x^2 + 4x + 8 = 0
Mkey [24]

Answer:

x = -2 + 2 i or x = -2 - 2 i

Step-by-step explanation:

Solve for x:

x^2 + 4 x + 8 = 0

Subtract 8 from both sides:

x^2 + 4 x = -8

Add 4 to both sides:

x^2 + 4 x + 4 = -4

Write the left hand side as a square:

(x + 2)^2 = -4

Take the square root of both sides:

x + 2 = 2 i or x + 2 = -2 i

Subtract 2 from both sides:

x = -2 + 2 i or x + 2 = -2 i

Subtract 2 from both sides:

Answer:  x = -2 + 2 i or x = -2 - 2 i

8 0
3 years ago
What is 2 to the power of three halves equal to?
Kruka [31]
I think the answer is 2.8
3 0
3 years ago
Read 2 more answers
Katherine and Shally had $288 altogether. Katherine gave 1/3 of her share to Shally and their father gave $68 to Shally. They no
erastova [34]
1/3 of $288 is $96 So, therefore Shally had $96 at first.
But They both didn't have the same amount of money after too because:
1/3 of $288 is $96 
$96 + $68 = $164     So Shally has $164

Now, $288 - $96 = $192.    So Katherine has $192

So therefore they did not have the same amount of money but 1/3 of $288 is $96
 

4 0
3 years ago
In how many ways can a quality-control engineer select a sample of3 transistors for testing frm a batch of 100 transistors?
Advocard [28]

Answer:

161700 ways.

Step-by-step explanation:

The order in which the transistors are chosen is not important. This means that we use the combinations formula to solve this question.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this question:

3 transistors from a set of 100. So

C_{100,3} = \frac{100!}{3!(100-3)!} = 161700

So 161700 ways.

6 0
3 years ago
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