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gizmo_the_mogwai [7]
3 years ago
8

Peggy is an astronaut and volunteers for the first manned mission to Alpha Centauri, the nearest star system to the Solar System

. Her spacecraft will travel at 80%80% of the speed of light, and the trip there and back will take over 1010 years. Her twin sister Patty is an astronomer and will remain on Earth, studying Alpha Centauri using telescopes. When Peggy returns from her trip, how will their ages compare?
Physics
1 answer:
Flauer [41]3 years ago
5 0

Answer:

If Patty remains on Earth then at the time Peggy will come back from her trip, Peggy will be much younger than her sister Patty because of time-dilation.

Explanation:

Peggy and Patty are sisters. Peggy is an astronaut and Patty is an astronomer.

Peggy goes for mission to Alpha Centauri, the nearest star system to the Solar System at 80% of the speed of light, and will come back after 1010 years.

If Patty remains on Earth then at the time Peggy will come back from her trip, Peggy will be much younger than her sister Patty because of time dilation.

This is due to the fact that time moves slower in Alpha Centauri because of its massive gravitational force which bends space time. Moreover, It is known that Peggy's spacecraft moves at 80% of the speed of light, it will result in velocity time dilation since time moves slow if you travel at a speed near to the speed of light.

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Concave mirror ______the rays of light​
Step2247 [10]

Answer: A concave mirror focuses rays of light

Explanation:

3 0
3 years ago
ustapha Jones is speeding on the interstate in his Ferrari at 231km/hr when he passes a police car at rest . If the cop accelera
Lena [83]

Answer:

461 km/h

Explanation:

In order to solve this problem we must first sketch a drawing of what the situation looks like so we can better visualize it. (See attached picture).

We have two situations there, the first one is Mustapha's car that is traveling at a constant speed of 231km/hr.

The second situation is the police that is accelerating from rest until he reaches Mustapha. (We are going to suppose the acceleration is constant and that he will not stop accelerating until he reaches Mustapha). He has an acceleration of 15m/s^{2}.

We want to find what the final velocity of the police is at the time he reaches Mustapha. From this we can imply that the displacement x will be the same for both particles.

So let's model the first situation.

The displacement of Mustapha can be found by using the following equation:

V_{M}=\frac{x}{t}

when solving the equation for the displacement x we get that it will be:

x=V_{M}t

Now let's model the displacement of the cop. Since the cop has a constant acceleration, we can model his displacement with the following formula.

x=V_{0}t+\frac{1}{2}at^{2}

Since the initial velocity of the cop is zero, we can get rid of that part of the equation leaving us with:

x=\frac{1}{2}at^{2}

We can now set both equations equal to each other so we get:

\frac{1}{2}at^{2}=V_{M}t

When solving this for t, we get that:

t=\frac{2V_{M}}{a}  (let's call this equation 1)

Now, we know the cop has constant acceleration, so we can model it with the following formula too:

a=\frac{V_{f}-V_{0}}{t}

since the initial velocity of the cop is zero, we can get rid of that here too, so we get the following formula:

a=\frac{V_{f}}{t}

when solving for the final velocity, we get that:

V_{f}=at  (let's call this equation 2)

when substituting equation 1 into equation 2 we get:

V_{f}=a(\frac{2V_{M}}{a})

we can now cancel a leaving us with:

V_{f}=2V_{M}

This tells us that the final velocity of the cop will not depend on his acceleration. (This is only if the acceleration is constant all the time) So we get that the final velocity of the cop is:

V_{f}=2(231km/hr)

so

V_{f}=461km/hr

which is our answer.

8 0
3 years ago
Countries create quotas and tariffs to increase the volume of trade with their neighbors.
Svetach [21]

Oooooo, that statement is not true.  Countries create quotas and tariffs to <em>LIMIT</em> the volume of trade with other countries, including their neighbors.

6 0
3 years ago
Read 2 more answers
Light-rail passenger trains that provide transportation within and between cities speed up and slow down with a nearly constant
Reika [66]

Answer:

v = 21 m / s

Explanation:

We can solve this exercise with the kinematics equations, let's start by finding the acceleration of the train with the initial data

            v = v₀ + a t

the initial speed is the speed within the city 6 m / s, the final speed is v = 11 m / s and the time is t = 8 s

             a = (v-v₀) / t

             a = (11 - 6) / 8

             a = 0.625 m / s²

when it leaves the city with speed vo = 11 m / s it accelerates for t = 16 s

            v = v₀ + a t

            v = 11 + 0.625 16

             v = 21 m / s

4 0
4 years ago
If 1.34 ✕ 1020 electrons move through a pocket calculator during a full day's operation, how many coulombs of charge moved throu
ioda

Given :

Number of operations move through a pocket calculator during a full day's operation , n=1.34 \times 10^{20} .

To Find :

How many coulombs of charge moved through it .

Solution :

We know , charge in  one electron is :

e^-=-1.6\times 10^{-19}\ coulombs

So , charge on n electron is :

C=e^-\times n\\C=-1.6\times 10^{-19}\times 1.34\times 10^{20} \ C\\C=-21.44\ C

Therefore , -21.44 coulombs of charge is moved through it .

Hence , this is the required solution .

3 0
3 years ago
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