The electrostatic force is directly proportional to the product of the charges, by Coulomb's law.
F α Qq
If the charges are now half the initial charges:
<span>F α (1/2)Q *(1/2)q
</span>
F α (1/4)Q<span>q
The new force when the charges are each halved is (1/4) the first initial force experienced at full charge.</span>
Answer:
Well,
Explanation:
In a wave, energy is transported without the transport of water. Basically, a wave can be described as a disturbance that travels through a medium, transporting energy from one location to another location without transporting matter.
Answer:

Explanation:
Given:
electric field, 
charge, 
initial position coordinates, 
final position coordinates, 
We find the distance through which the charge has been moved:

Where we have (x1,y1) & (x2,y2) as the initial and final coordinates of the points.


Now we need the angle through which displacement is made with respect to the direction of electric field.

![\theta= tan^{-1}[\frac{76-(-131)}{107-(-81)} ]](https://tex.z-dn.net/?f=%5Ctheta%3D%20tan%5E%7B-1%7D%5B%5Cfrac%7B76-%28-131%29%7D%7B107-%28-81%29%7D%20%5D)

Now from the relation between the change in potential difference:



∵The change in voltage is defined as the work done per unit charge.
∴

Putting the respective values


Until the object starts to move, the static coefficient of friction must be used since the object is at rest initially. If the horizontal force is large enough to overcome the friction force and the object accelerates, we switch to the kinetic coefficient.
The total downward force in the -y direction is the weight plus the applied 26N:
Fy=mg-26N = 5*-9.81-26 = -75.05N
The maximum friction force here is the magnitude of this force times the static coefficient of friction. This force will point in the opposite direction as an applied horizontal force, no matter which way it points (non conservative forces tend to oppose motion in all directions)
Ff=75.05N*1.03=77.3N
Note this is greater than the applied horizontal x-directed force of 26N. This means the answer is 26N of friction force acting on the object. Why not the full 77.3N? Because that is the maximum amount you can oppose along the x-direction before the object starts to move. But since we are only applying 26N, that is all the friction force pushes back with. This is a statement of Newton's 3rd Law of equal and opposite actions. If the object pushed back with the full 77.3N in this case it would accelerate backward (F=ma), since there would be a net force on the object (77.3N - 26N = 51.3N) This obviously doesn't happen!
The point is is you talking about the point is medium a a highlighter and it’s a reflection because it is a lighter color medium B has a higher index of refraction because it’s a darker go to medium because a higher end