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ElenaW [278]
3 years ago
7

If 1.34 ✕ 1020 electrons move through a pocket calculator during a full day's operation, how many coulombs of charge moved throu

gh it?
Physics
1 answer:
ioda3 years ago
3 0

Given :

Number of operations move through a pocket calculator during a full day's operation , n=1.34 \times 10^{20} .

To Find :

How many coulombs of charge moved through it .

Solution :

We know , charge in  one electron is :

e^-=-1.6\times 10^{-19}\ coulombs

So , charge on n electron is :

C=e^-\times n\\C=-1.6\times 10^{-19}\times 1.34\times 10^{20} \ C\\C=-21.44\ C

Therefore , -21.44 coulombs of charge is moved through it .

Hence , this is the required solution .

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The block A and attached rod have a combined mass of 50 kg and are confined to move along the guide under the action of the 796-
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Answer:

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Explanation:

From the given information;

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\sum F_x = ma_x \\ \\ 796 - 50(9.81) sin 66=50a \\ \\ 796 - 448.094 = 50 a  \\ \\ a = \dfrac{347.906}{50} \\ \\ a  = 6.96 \ m/s^2

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From the second part of the diagram:

\sum M_B = mad \\ \\ M - (15 \times 9.81) (1.5) = (25 \times 6.96)(1.5 sin 66) \\ \\ M - 220.725 = 238.435  \\ \\  M = 238.435 + 220.725 \\ \\  \mathbf{M = 459.16 \ N.m}

6 0
3 years ago
Technician A says that if starter drive clearance is too small, the starter will produce a noise during cranking. Technician B s
Ronch [10]

Answer:

Both Technicians A and B are wrong in there answers.

Explanation:

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The starter and the driven component(gear) are supposed to fit closely, with some clearance between the two gears so as to operate without noise. When the<u> clearance is too small </u>there will be a <u>noise after cranking,</u>  and   when the <u>clearance is too great</u> there be <u>noise before cranking</u>.

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3 years ago
What is projectile motion
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A naval engineer is testing an nonreflective coating for submarines that would help them avoid detection by producing destructiv
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Answer:

5 cm .

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For waves getting reflected from both layers of the coating ,  undergoing phase reversal , net change will be zero .

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path diff = ( 2n+1) λ / 2

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