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AlekseyPX
4 years ago
11

Explain why wedges and screws are actually types of inclined planes.

Physics
2 answers:
slava [35]4 years ago
5 0
<span>The screw is really just an inclined plane covered around with a tiny pole. The wedge is definitely an inclined plane, since it starts with a point, then rises getting thicker, as an inclined plane. </span>
oee [108]4 years ago
4 0
The screw is really an inclined plane cover around with a tiny pole. The wedge is definitely an inclined plane, sinse it starts with  point, then rises getting thicker, as on inclined plane.
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A singer raises his pitch one octave. what quality of the sound wave has changed? the frequency has increased. the wavelength ha
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The frequency has increased.
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An electric motor that transforms 1000 J of chemical potential energy into 975 J of kinetic energy and 25 J of wasted heat energ
Musya8 [376]

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97.5% I believe

Explanation:

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8 0
3 years ago
A gamma-ray photon produces an electron and a positron, each with a kinetic energy of 261 keV . h=6.626×10−34J⋅s, c=2.998×108m/s
ddd [48]

Answer:

The energy and the wavelength of the photon are 1.546 MeV and 8.036\times10^{-13}\ m.

Explanation:

Given that,

Kinetic energy = 261 KeV

Planck's constant h = 6.626\times10^{−34}\ J.s

Speed of light c=2.998\times10^{8}\ m/s

Mass of electron m_{e}=9.109\times10^{-31}\ kg

Charge q=1.602\times10^{-19}\ C

(A). We need to calculate the energy of the photon

Using formula of rest mass energy

E=m_{0}c^2

E=9.109\times10^{-31}\times(3\times10^{8})^2

E=8.198\times10^{-14}\ J

Energy in eV

E=\dfrac{8.198\times10^{-14}}{1.6\times10^{-19}}

E=512375\ eV

E=0.512\ MeV

The total energy of photon

TE=2(E+K.E)

TE=2(0.512+0.261)

TE=1.546\ MeV

(B). We need to calculate the wavelength of the photon

Using formula of wavelength

\lambda=\dfrac{hc}{E}

Put the value into the formula

\lambda=\dfrac{6.626\times10^{−34}\times3\times10^{8}}{1.546\times10^{6}\times1.6\times10^{-19}}

\lambda=8.036\times10^{-13}\ m

Hence, The energy and the wavelength of the photon are 1.546 MeV and 8.036\times10^{-13}\ m.

7 0
3 years ago
Explain the difference between contact and non-contact forces. Give an example of each
Amiraneli [1.4K]

pushing on something that pushes back = action and reaction.

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1. A 1.32 x 104 meter steel railroad track with a coefficient of linear expansion of 12 x 10-6 per degree Celsius changes temper
GarryVolchara [31]

Answer:

1) 0.1584 m

2) To allow for expansion without derailment

3) 0.101376 m

4) 213.675 °C

5) 266.67 m

6) 8.33 × 10⁻⁶ /°C

7) The alloy meets the requirement

8) 1.95 × 10⁻³ /°C

9) 32.095 m

10) -12157.72°C

Explanation:

1) Equation for the coefficient of linear expansion = \frac{\Delta L}{L} = \alpha _L \Delta T

Where:

ΔL = Change in length = Required

L = Initial length = 1.32 × 10⁴ m

\alpha _L = Coefficient of linear expansion of steel = 12 × 10⁻⁶ /°C

ΔT = Change in temperature = 37°C - 27°C = 10°C

Plugging the values in the equation for the temperature expansion of steel, we have m;

ΔL = L × \alpha _L ×ΔT = 1.32 × 10⁴ × 12 × 10⁻⁶ × 10  = 0.1584 m

2. Here we have that by segmenting railroad tracks into short pieces, the expansion of the metal tracks with temperature can be absorbed by the gaps between the segment without distorting the shape and direction (pattern) of the tracks

3. Here we have;

\alpha _L = Coefficient of linear expansion of iron = 12 × 10⁻⁶ /°C

ΔT = Temperature change = 27°C - 3°C = 24°C

L = Height of the Eiffel Tower = 352 meters

∴ ΔL = L × \alpha _L ×ΔT = 352 × 12 × 10⁻⁶ × 24 = 0.101376 m

Therefore, the height of the Eiffel Tower changes from 352 m to about 352.101376 m each year, with an average change in height experienced each year = 0.101376 m

4. Here, we have

L = 13.0 ft

ΔL = 1 in.

\alpha _L = 30 × 10⁻⁶ /°C

ΔT = Required temperature change

From  \frac{\Delta L}{L} = \alpha _L \Delta T

\Delta T =\frac{\Delta L}{L \times  \alpha _L} = \frac{1}{156 \times 30 \times 10^{-6}} = 213.675^{\circ}C

5. Here, we have;

L = \frac{\Delta L}{\alpha _L \Delta T}

∴ L = 1/(150×25 × 10⁻⁶) = 266.67 m

The bars original length = 266.67 m

6. Here we have;

\alpha _L = \frac{\Delta L}{L \times \Delta T}

Where:

ΔL = 3.00 - 3.002 = 0.002 m

L = 3.00 m

ΔT = 110°C - 30°C = 80°C

∴ \alpha _L = 0.002/(3.00 × 80) = 8.33 × 10⁻⁶ /°C

7. Here we have;

ΔL = L × \alpha _L ×ΔT = 3 × 8.33 × 10⁻⁶ × 210 = 0.00525 m

Therefore, final length = 3.00 m + 0.00525 m = 3.00525 m

Since 3.00525 m < 3.017 m hence the alloy meets the requirement.

8. Here, we have

L = 3.2 m

ΔL = 0.5 m

ΔT = 84°C - 24°C = 60°C

∴ \alpha _L = 0.5/(3.2 × 60) = 1.95 × 10⁻³ /°C

The coefficient of linear expansion of the material from which the rod is made = 1.95 × 10⁻³ /°C

9. Here, we have

Length of steel girder, L = 32.10 m

ΔT = 8°C - 22°C = -14°C

\alpha _L = 12 × 10⁻⁶ /°C

ΔL = L × \alpha _L ×ΔT

Hence ΔL = 32.1 × 12 × 10⁻⁶× -14 = -0.0054 m

New length = 32.1 - 0.0054 = 32.095 m

10. Here we have;

ΔL = 92.6 cm - 123 cm  = -30.4 cm

\alpha _L = 2.0 × 10⁻⁵ /°C

L = 123 cm

∴ \Delta T =\frac{\Delta L}{L \times  \alpha _L} = \frac{-30.4}{123 \times 2.0 \times 10^{-5}} = -12357.724^{\circ}C

Therefore, the temperature will be 200 - 12357.724 = -12157.72°C.

3 0
3 years ago
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