Answer:
<h2>153J</h2>
Explanation:
Step one:
given data
mass m= 8.5kg
radius r= 10cm in meters = 0.01m
velocity v= 6m/s
The work done will be the same as the energy possessed by the sphere at such speed
Required
the work one in Joules
we know that
KE=1/2mv^2
KE=1/2*8.5*6^2
KE= 1/2*8.5*36
KE=306/2
KE=153J
Answer:
The force is "19 µN".
Explanation:
The lane's j-component is meaningless, as the current is flowing in the -j line.
Therefore the power is now in the direction of + z (out of the page if x and y are in the page plane) and has the magnitude.
The shortest and straight ones
Answer:
Option C. 16.6 m/s
Explanation:
To round this 16.558 m/s to 3sf, we need to count the number beginning from 1. When we get to the 3rd number( ie 5), we'll examine the fourth number(i.e 5)to see if it less than five or greater. If it less than five, then we'll discard it. But if it five or greater, we'll approximate it and add it to the 3rd number.
So.
16.558 m/s = 16.6m/s to 3sf
3 is false 2 is true and the rest true
