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Feliz [49]
3 years ago
15

A painter mixes 2 1/2 pints of yellow paint with 4 pints of red paint to make a certain shade of orange paint. How many pints of

yellow paint should be mixed with 10 pints of red paint to make this shade of orange?
Mathematics
2 answers:
9966 [12]3 years ago
7 0

Answer:

6

Step-by-step explanation:

A painter mixes 2 1/2 pints (2.5 pints) of yellow paint with 4 pints of red paint to make a certain shade of orange paint. The ratio of yellow paint to red paint is 2.5:4. In order to find the pints of yellow paint needed to be mixed with 10 pints of red paint, we will use conversion fractions.

10 red pints × (2.5 yellow pints/ 4 red pints) ≈ 6 pints (we round off to 1 significant figure)

Natasha2012 [34]3 years ago
4 0

For every 4 pints of red, there are 2 1/12 pints of yellow. 8 of those red pints would make 5 yellow pints. Adding 2 more pints of red to get to the 10 would mean you have to half the 2 1/2, which would be 1 1/2. So, you would need 6 1/2 pints of yellow mixed with the 10 red pints to make the shade of orange. :)

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2 angles are Complementary, if the sum of their measures = 90°.

Let the 2 angles be A and B, and let their measures be m(A)=a, m(B)=b.

Let A be the larger angle.



"the larger angle is six more than three times the smaller angle."

can be 'translated' into algebra as:   a = 6 + 3b

Also, since A and B are complementary, we have a+b=90°.


substitute a=6+3b in the second equation:

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4b=90°-6°

b=84°/4=21°



Then, a = 90°-21°=69°


Answer: a= 69°, b=21°
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