In balancing half-reactions, it is important to know if the medium is basic or acidic. For basic medium, what is added to the reactant side is the hyroxide ion OH- and what is added to the other side is H2O. The answer is the fifth option.
R = 1.3 A° = 1.3 × 10^(-10) m
V = 9.20277208×10^(−30) m.
<span>Generally, a hydrogen bond can be characterized as a proton shared by two lone electron pairs. It occurs when a hydrogen (H) atom, covalently bound to a highly electronegative atom such as nitrogen (N), oxygen (O), or fluorine (F), experiences the electrostatic field of another highly electronegative atom nearby.
Among the choices in the bond (-N...H-O) one side of the Hydrogen is bonded to a highly electronegative atom with a lone pair (-N) and the other side is directly bonded with a highly electronegative atom (O-).
So -N...H-O- shows a hydrogen bond.</span>
Petrified fossils, they are made of wood that becomes petrified from pressure and lack of oxygen.
Answer:
1 mole of CO2 and 2 mole H2O will be produced in the reaction.
Explanation:
N:B: I guess it will be 6 moles of O2 not CO2.
Balanced Equation: CH4 + 2O2 --> CO2 + 2H2O
Given,
1 mole CH4
6 moles of O2
According to Stoichiometry,
In the reaction,
2 mole O2 reacts with 1 mole CH4
1 mole O2 reacts with 1/2 mole CH4
∴6 mole O2 reacts with (1/2)*6 mole CH4
= 3 moles of CH4
But, there is only 1 mole CH4 provided. So CH4 is the limiting reagent.
Now,
According to Stoichiometry,
In the reaction,
1 mole CH4 produces 2 moles of H2O
Again,
According to Stoichiometry,
In the reaction,
1 mole CH4 produces 1 mole CO2
So, 1 mole of CO2 and 2 mole H2O will be produced in the reaction.
N:B:[Doing calculation with limiting reagent in problems like these gives you the most accurate answer].
