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Gala2k [10]
4 years ago
5

Thomas has 235 grams of K2S in the chemistry lab. How many atoms of potassium (K) are in 235 grams of the compound?

Chemistry
1 answer:
kotykmax [81]4 years ago
5 0

Answer : The correct option is, (C)  2.57\times 10^{24}

Solution for Part 1 : Given,

Mass of K_2S = 235 g

Molar mass of K_2S = 110.262 g/mole

First we have to calculate the moles of K_2S.

\text{Moles of }K_2S=\frac{\text{Mass of }K_2S}{\text{Molar mass of }K_2S}=\frac{235g}{110.262g/mole}=2.13moles

Now we have to calculate the number of atoms of potassium in the given compound.

In the given compound, there are 2 atoms of K and 1 atom of S.

As, 1 mole contains 2\times 6.022\times 10^{23} number of potassium atoms

So, 2.13 moles contains 2.13\times 2\times 6.022\times 10^{23}=2.57\times 10^{24} number of potassium atoms

Therefore, the number of potassium atoms in given compound is,  2.57\times 10^{24}

Explanation for Part 2 :

Statement 1 : A balloon shrinks when it's taken outside in the winter.

This statement follow the Charles's law. There is a direct relation between the temperature and volume. As the temperature decreases, the volume also decreases and vice-versa.

Statement 2 : A closed, flexible container expands when it's heated.

This statement follow the Charles's law. There is a direct relation between the temperature and volume. As the temperature increases, the volume also increases and vice-versa.

Statement 3 : When the size of an air chamber is increased, the air pressure decreases.

This statement follow the Boyle's law. There is an inverse relation between the pressure and volume. As the pressure decreases, the volume increases and vice-versa.

Statement 4 : Pressing on an inflated balloon decreases its size.

This statement follow the Boyle's law. There is an inverse relation between the pressure and volume. As the pressure increases, the volume decreases and vice-versa.

Statement 5 : A balloon expands when air is blown into it.

This statement follow the Avogadro's law. There is a direct relation between the number of moles of gas and volume. As the number of moles of air increases, the volume also increases and vice-versa.

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