In ΔFGH, the measure of ∠H=90°, GF = 41, HG = 40, and FH = 9. What ratio represents the cosine of ∠F?
2 answers:
Answer:
Cosine F = (40 / 41)
Step-by-step explanation:
Since it's a right angle triangle, we can use
SOHCAHTOA method.
Where CAH = cosine F = adjacent / hypotenus.
Opposite (FH) = 9
Adjacent (HG) = 40
Hypothenus(FG) = 41
Cosine F = adjacent / hypothenus
Cosine F = 40 / 41
Cosine F = 0.9756
F = cos⁻(0.9756)
F = 12.68°
See attached document for better illustration on the triangle.
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Answer:
<h2>16kg</h2>Step-by-step explanation:
This problem is borers on elasticity of materials.
according to Hooke's law,<em> "provided the elastic limit of an elastic material is not exceeded the the extension e is directly proportional to the applied force."</em>
where F is the applied force in N
k is the spring constant N/m
e is the extension in meters
Given data
mass m= 24kg
extensnion=15cm in meters= =
we can solve for the spring constant k
we also know that the force F = mg
assuming
therefore
We can use this value of k to solve for the mass that will cause an extension of