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3 years ago

What's responsible for eutrophication in seawater

Chemistry

2 answers:

Afina-wow [57]3 years ago

6 0

Answer:

What's responsible for eutrophication in seawater

Explanation:

Runoff of artificial fertilizers

Schach [20]3 years ago

5 0

Answer:

Some of the causes of eutrophication of seawater are: high concentrations of inorganic matter, sudden changes in temperature, changes in the pH of water and the ability of some organisms to adapt to adverse conditions.

Explanation:

Eutrophication is the process through which lakes, streams, or bays become overloaded with nutrient-rich water. When this occurs, large blooms of algae are produced and when the algae die, microorganisms in the water feed on the remains and consequently use up the available oxygen in the water. This leaves little oxygen for fish and other aquatic animals, resulting in the suffocation of aquatic life. Some of the responsables are:

Presence of higher concentrations of dissolved inorganics: nitrates, phosphates and silicates and carbon.
A rise in temperature, dearth of dissolved oxygen, rapid fluctuation in pH-resulting in the absence of higher trophic level consumers.
Ability of certain species under some genera to withstand or adapt to adverse conditions and resultantly out-competing other in terms of dominance.

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In two or more complete sentences, describe how one of the occupations that you studied would use descriptive statistics when pe

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4 years ago

Using any data you can find in the ALEKS Data resource, calculate the equilibrium constant at for the following reaction. N2(g)H

soldier1979 [14.2K]

<u>Answer:</u> The equilibrium constant for this reaction is $5.85\times 10^{5}$

<u>Explanation:</u>

The equation used to calculate standard Gibbs free change is of a reaction is:

$\Delta G^o_{rxn}=\sum [n\times \Delta G^o_{(product)}]-\sum [n\times \Delta G^o_{(reactant)}]$

For the given chemical reaction:

$3H_2(g)+N_2(g)\rightarrow 2NH_3(g)$

The equation for the standard Gibbs free change of the above reaction is:

$\Delta G^o_{rxn}=[(2\times \Delta G^o_{(NH_3(g))})]-[(1\times \Delta G^o_{(N_2)})+(3\times \Delta G^o_{(H_2)})]$

We are given:

$\Delta G^o_{(NH_3(g))}=-16.45kJ/mol\\\Delta G^o_{(N_2)}=0kJ/mol\\\Delta G^o_{(H_2)}=0kJ/mol$

Putting values in above equation, we get:

$\Delta G^o_{rxn}=[(2\times (-16.45))]-[(1\times (0))+(3\times (0))]\\\\\Delta G^o_{rxn}=-32.9kJ/mol$

To calculate the equilibrium constant (at 25°C) for given value of Gibbs free energy, we use the relation:

$\Delta G^o=-RT\ln K_{eq}$

where,

$\Delta G^o$ = standard Gibbs free energy = -32.9 kJ/mol = -35900 J/mol (Conversion factor: 1 kJ = 1000 J )

R = Gas constant = 8.314 J/K mol

T = temperature = $25^oC=[273+25]K=298K$

$K_{eq}$ = equilibrium constant at 25°C = ?

Putting values in above equation, we get:

$-32900J/mol=-(8.314J/Kmol)\times 298K\times \ln K_{eq}\\\\K_{eq}=e^{13.279}=5.85\times 10^{5}$

Hence, the equilibrium constant for this reaction is $5.85\times 10^{5}$

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3 years ago

What are the component of black powder and why are they needed to cause an explosion

melisa1 [442]

Hi There!

Black powder is an explosive powder consisting of saltpeter, sulfur, and charcoal, used chiefly in old guns fired for sport, in fireworks, and for spotting charges in practice bombs; black gunpowder.

In addition to being easily ignited by friction and impact, black powder is also extremely sensitive to flame and spark. It ignites violently when unconstrained and explodes when lit in even the slightest amount of confinement.

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2 years ago

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