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sweet-ann [11.9K]
3 years ago
13

How many moles of oxygen are necessary to completely react with propane (C3H8) to produce 16.3 mol of water according to the fol

lowing balanced chemical equation? ________________________________________________________________________ C3H8 + 5 O2 -> 3 CO2 + 4 H2O
I tried doing these they are due by 12:00 please help i have 2 more like this
Chemistry
2 answers:
Schach [20]3 years ago
8 0

Answer:

20.375 moles of oxygen are necessary to completely react with propane to produce 16.3 moles of water.

Explanation:

C_3H_8 + 5O_2\rightarrow 3 CO_2 + 4H_2O

Mole sof water formed = 16.3 moles

According to reaction , 4 moles of water are obtained from 5 moles of oxygen.

Then 16.3 moles of oxygen will be obtained from:

\frac{5}{4}\times 16.3 mol =20.375 mol of oxygen

20.375 moles of oxygen are necessary to completely react with propane.

velikii [3]3 years ago
4 0
The balanced chemical reaction is expressed as:

<span>C3H8 + 5 O2 -> 3 CO2 + 4 H2O

We are given the amount of water produced. We use this amount for the calculations. We do as follows:

16.3 mol H2O ( 1 mol C3H8 / 4 mol H2O ) = 4.075 mol C3H8 needed

Hope this answers the question. Have a nice day.</span>
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The energy of the photon from the calculation performed is 3.5 * 10^-16 J.

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Now we have that;

E = 6.6 * 10^-34 * 3 * 10^8/562 * 10^-9

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by using ICE table:

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            BaCrO4(s)    →  Ba^2+(aq)    +   CrO4^2-(aq)

initial                               0                          0

change                          +X                       +X 

Equ                                  X                         X


when Ksp = [Ba^2+][CrO4^2-]

by substitution:

2.1 x 10^-10 = X* X

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According to the reaction equation:

            BaCrO4(s)  →  Ba^2+(aq)    +   CrO4^2-(aq)

initial                                 0                      0.0016

Change                           +X                      +X

Equ                                   X                      X+0.0016

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by substitution:

2.1 x 10^-10 = X*(X+0.0016) by solving for X 

∴ X = 1.3 x 10^-7

∴ solubility =X = 1.3 x 10^-7

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