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sweet-ann [11.9K]
3 years ago
13

How many moles of oxygen are necessary to completely react with propane (C3H8) to produce 16.3 mol of water according to the fol

lowing balanced chemical equation? ________________________________________________________________________ C3H8 + 5 O2 -> 3 CO2 + 4 H2O
I tried doing these they are due by 12:00 please help i have 2 more like this
Chemistry
2 answers:
Schach [20]3 years ago
8 0

Answer:

20.375 moles of oxygen are necessary to completely react with propane to produce 16.3 moles of water.

Explanation:

C_3H_8 + 5O_2\rightarrow 3 CO_2 + 4H_2O

Mole sof water formed = 16.3 moles

According to reaction , 4 moles of water are obtained from 5 moles of oxygen.

Then 16.3 moles of oxygen will be obtained from:

\frac{5}{4}\times 16.3 mol =20.375 mol of oxygen

20.375 moles of oxygen are necessary to completely react with propane.

velikii [3]3 years ago
4 0
The balanced chemical reaction is expressed as:

<span>C3H8 + 5 O2 -> 3 CO2 + 4 H2O

We are given the amount of water produced. We use this amount for the calculations. We do as follows:

16.3 mol H2O ( 1 mol C3H8 / 4 mol H2O ) = 4.075 mol C3H8 needed

Hope this answers the question. Have a nice day.</span>
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NemiM [27]

Answer:

b. One electron state is an anti-bonding orbital, which results in an absence of electron density between atoms.

Explanation:

8 0
3 years ago
2. Consider the reaction 2 Cg H18 (4) +250â (9) ⺠16 co, (g) + 18 HâO(g) la How many moles of H20co) are produced, when |--16:1
Sladkaya [172]

Answer :

(a) The moles of water produced are 145.35 moles.

(b) The mass of oxygen needed are 3080.8 grams.

<u>Solution for part (a) : Given,</u>

Moles of C_8H_{18} = 16.15 moles

First we have to calculate the moles of H_2O

The balanced chemical reaction is,

2C_8H_{18}+25O_2\rightarrow 16CO_2+18H_2O

From the balanced reaction we conclude that

As, 2 moles of C_8H_{18} react to give 18 moles of H_2O

So, 16.15 moles of C_8H_{18} react to give \frac{16.15}{2}\times 18=145.35 moles of H_2O

The moles of water produced are 145.35 moles.

<u>Solution for part (b) : Given,</u>

Mass of C_8H_{18} = 878 g

Molar mass of C_8H_{18} = 114 g/mole

Molar mass of O_2 = 32 g/mole

First we have to calculate the moles of C_8H_{18}.

\text{ Moles of }C_8H_{18}=\frac{\text{ Mass of }C_8H_{18}}{\text{ Molar mass of }C_8H_{18}}=\frac{878g}{114g/mole}=7.702moles

Now we have to calculate the moles of O_2

The balanced chemical reaction is,

2C_8H_{18}+25O_2\rightarrow 16CO_2+18H_2O

From the balanced reaction we conclude that

As, 2 moles of C_8H_{18} react with 25 moles of O_2

So, 7.702 moles of C_8H_{18} react with \frac{7.702}{2}\times 25=96.275 moles of O_2

Now we have to calculate the mass of O_2.

\text{ Mass of }O_2=\text{ Moles of }O_2\times \text{ Molar mass of }O_2

\text{ Mass of }O_2=(96.275moles)\times (32g/mole)=3080.8g

The mass of oxygen needed are 3080.8 grams.

6 0
2 years ago
Which of the following has the correct name for either the acid or base
Vlad1618 [11]

Answer:

Explanation:

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6 0
3 years ago
A sample of pure tin metal is dissolved in nitric acid to produce 15.00 mL of solution containing Sn2+. When this tin solution i
Rudik [331]

Answer:

1.00 M

Explanation:

Sn^2+ reacts with KMNO4 as follows;

5Sn^2+(aq) + 2MnO4^-(aq) + 16H^+(aq) ----> 5Sn^4+(aq) + 2Mn^+(aq) + 8H2O(l)

The number of moles of MnO4^- reacted = 42.1/1000 L × 0.145 mol/L

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x= 5 × 0.0061/2

x= 0.015 moles

Since the volume of the Sn^2+ solution is 15.00mL or 0.015 L

number of moles = concentration × volume

Concentration = number of moles/volume

Concentration= 0.015 moles/0.015 L

Concentration = 1 M

6 0
3 years ago
PLEASE ANSWER QUICKLY I'M IN A TEST
Natasha_Volkova [10]

D is the correct answer......

hope it help, please thank me if it did.....

4 0
2 years ago
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