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3 years ago

What's the molality of a solution with 120 g of NaCl and 30 kg of water?

Chemistry

1 answer:

pogonyaev3 years ago

4 0

Answer: The correct option is A) 0.068 m

Explanation:

Molality is defined as the amount of solute expressed in the number of moles present per kilogram of solvent. The units of molarity are mol/kg. The formula used to calculate molarity:

$\text{Molality of solution}=\frac{\text{Given mass of solute}}{\text{Molar mass of solute}\times \text{Mass of solvent (in kg)}}$ .....(1)

We are given:

Given mass of NaCl = 120 g

Molar mass of NaCl = 58.45 g/mol

Mass of solvent = 30 kg

Putting values in equation 1, we get:

$\text{Molality of NaCl}=\frac{120}{58.44\times 30}\\\\\text{Molality of NaCl}=0.068m$

Hence, the correct option is A) 0.068 m

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A sample of NO2 in a 1550 mL metal cylinder at 70.26 kPa has its temperature changed from 480oC to -237oC while its volume is si

antoniya [11.8K]

Answer:

1.02KPa

Explanation:

The following were obtained from the question:

V1 = 1550mL

P1 = 70.26kPa

T1 = 480°C = 480 + 273 = 753K

T2 = -237°C = - 237 + 273 = 36K

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P2 =?

The final pressure can obtain as follows:

P1V1/T1 = P2V2/T2

(70.26x1550)/753 = (P2x5114)/36

Cross multiply to express in linear form as shown below:

P2 x 5114 x 753 = 70.26 x 1550 x 36

Divide both side by 5114 x 753

P2 = (70.26x1550x36)/(5114x753)

P2 = 1.02KPa

Therefore, the final pressure is 1.02KPa

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Answer:

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