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rosijanka [135]
3 years ago
8

Predict the precipitate that will be formed in the following reaction: NaF(aq) + AgNO3(aq) →

Chemistry
1 answer:
netineya [11]3 years ago
8 0

The precipitate that will be formed : AgF

<h3>Further explanation</h3>

One indication of the double displacement reaction is the precipitation reaction

Solubility Rules:  

• 1. soluble compound  

All compounds of Li +, Na +, K +, Rb +, Cs +, and NH4 +  

All compounds of NO₃⁻ and C₂H₃O₂⁻  

Compounds of Cl−, Br−, I− except Ag⁺, Hg₂²⁺, Pb²⁺  

Compounds of SO₄²⁻ except for Hg₂²⁺, Pb²⁺, Sr²⁺, Ba²⁺  

• 2. insoluble compounds  

Compounds of CO₃²⁻ and PO₄³⁻ except for Compounds of Li +, Na +, K +, Rb +, Cs +, and NH₄ +  

Compounds of OH− except Compounds of Li +, Na +, K +, Rb +, Cs +, NH₄⁺, Sr²⁺, and Ba²⁺  

Reaction

NaF(aq) + AgNO₃(aq) →NaNO₃(aq)+ AgF(s)

From the solubility rules above, it has been shown that the salts of the Ag⁺ cations are insoluble salts

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You are given 50.0 ml of 1.50 m hno3. how many ml of 0.81 m naoh are needed to neutralize it?
svet-max [94.6K]
V(HNO₃) = 50.0 mL in liters = 50.0 /1000 =0.05 L
M(HNO₃) = 1.50 M

Number of moles HNO₃ :

n = M x V

n = 1.50 x 0.05

n = 0.075 moles of HNO₃

HNO₃ + NaOH = H₂O + NaNO₃

1 mole HNO₃ -------- ---1 mole NaOH
0.075 moles HNO₃ ---- ?

moles NaOH = 0.075 * 1 / 1

 = 0.075 moles of NaOH

V ( NaOH ) :

M = n / V

0.81 = 0.075 / V

V = 0.075 / 0.81

V =<span> 0.0925 L or  92.5 mL </span>

<span>hope this helps!</span>
7 0
3 years ago
In a certain compound of iron and oxygen, FexOy, it is found that a sample of this compound weighing 6.285 g contains 4.396 g of
saveliy_v [14]

Answer:

Formula of oxide is Fe_{2}O_{3}

Explanation:

The given compound consists of Fe and O.

So, mass of oxygen in sample = (mass of sample) - (mass of Fe in sample)

                                                   = (6.285 g ) - (4.396 g)

                                                   = 1.889 g

Molar mass of O = 16 g/mol and molar mass of Fe = 55.845 g/mol

So, ratio of number of moles of Fe and O (Fe : O)

      = \frac{4.396}{55.845}:\frac{1.889}{16}

      = 0.0787 : 0.118

      = 1:\frac{0.118}{0.0787}

      = 1 : 1.5

      = 2 : 3

So, formula of oxide is Fe_{2}O_{3}

5 0
3 years ago
A gas sample contains 4.00 g of ch4 and 2.00 g of he. what is the volume of the sample at stp? 5.64 l 32.0 l 22.4 l 16.8 l 132 l
Phantasy [73]
The gas sample consists of CH₄ and He.
Number of CH₄ moles - 4 g/ 16 g/mol = 0.25 mol
molar volume is where 1 mol of any gas occupies a volume of 22.4 L 
Therefore 0.25 mol of CH₄ gas occupies a volume of 22.4 L/mol x 0.25 mol
Volume of methane - 5.6 L 
Number of He moles - 2.00 g/ 4 g/mol = 0.5 mol 
Volume occupied by He - 22.4 L /mol x 0.5 mol = 11.2 L
The total volume of the sample = 5.6 L + 11.2 L = 16.8 L 
4 0
4 years ago
A dull metal object has a density of 8.8 G/ML and a volume of 20 ML calculate the mass
Alex

Answer:

Mass = 0.000176 gram

Steps:

m =  V × ρ

=  20 milliliter × 8.8 gram/cubic meter

=  2.0E-5 cubic meter × 8.8 gram/cubic meter

=  0.000176 gram

Explanation:

8 0
3 years ago
Which subatomic particle plays the greatest part in determining the properties of and element?
alexandr1967 [171]
There are three subatomic particle that are present in an atom. These are electrons, protons, and neutrons. Among these three, I believe the <span>subatomic particle that plays the greatest part in determining the properties of and element would be the electron. It is what determines how the element would react in different conditions.</span>
3 0
3 years ago
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