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3 years ago

Write the number 0.000877 in words?

Mathematics

1 answer:

mariarad [96]3 years ago

4 0

Answer:

Eight hundreds seventy seven millionths.

Step-by-step explanation:

1. You have the folllowing number given in the problem above: 0.000877

2. As you can see, the whole part of 0.000877 is zero, therefore, to write it in words you must write the place value of the last digit on the decimal part.

3. In this case, the last digit is in the millionths place. Then, it is: eight hundreds seventy seven millionths.

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Midpoint of (-2,-4) and (2,1)

Mice21 [21]

I got it =4/5 hope it’s right

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3 years ago

I have to find the circumference of 15 cm

Pie

Answer:

r = 2.39 and C=2πr=2·π·2.39≈14.99997

Step-by-step explanation:

Using the formula

C=2πr

Solving for r=C 2π=15

2·π≈2.38732

and then u round up the 7 told the 8 to go up.

2.39

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3 years ago

A rocket is fired with an initial vertical velocity of 40 m/s from a launch pad 45 m high, and its height is given by the formul

N76 [4]

Answer:

1) 125 meters

2) For 9 seconds.

Step-by-step explanation:

The rocket's height is given by the formula $-5t^2+40t+45$ .

Notice that this is a quadratic.

Part 1)

Since this is a quadratic, the highest height the rocket goes will be the vertex of our quadratic. Remember that the vertex of a quadratic in standard form is:

$(-\frac{b}{2a}, f(-\frac{b}{2a}))$

So, let's identify our coefficients. The standard quadratic form is:

$ax^2+bx+c$

Therefore, in this case, our a is -5, b is 40, and c is 45.

So, let's find the x-coordinate of our vertex. Substitute 40 for b and -5 for a. This yields:

$x=\frac{-(40)}{2(-5)}$

Multiply and reduce. So:

$x=-40/-10=4$

Now, substitute 4 for t to find the height. So:

$-5(4)^2+40(4)+45$

Evaluate:

$=-5(16)+40(4)+45$

Multiply and add:

$=-80+160+45=125\text{ meters}$

Therefore, the highest the rocket goes up is 125 meters.

Part 2)

To find out for how much time the rocket is in the air, we can think about after how many seconds after launch will the rocket land.

If the rocket lands, the height h will be 0. So, we can set our expression equal to 0 and solve for t:

$-5t^2+40t+45=0$

First, let's divide everything by -5. This yields:

$t^2-8t-9=0$

We can factor:

$(t+1)(t-9)=0$

Zero Product Property:

$t+1=0\text{ or } t-9=0$

Solve for t:

$t=-1\text{ or } t=9$

In this case, since t is our time in seconds, -1 seconds does not make sense. So, we can remove -1 from our solution set.

Therefore, 9 seconds after launch, the rocket will touch the ground.

Therefore, the rocket was in the air for 9 seconds.

And we're done!

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3 years ago

Aaron is using a special beaker in science that is a cylinder with a radius of 2 cm and a height of 3 cm on top of a cylinder th

Vilka [71]

Since in the above case, the beaker has two sections each with different radius and height, we will divide this problem into two parts.

We will calculate the volume of both the beakers separately and then add them up together to get the volume of the beaker.

Given, π = 3.14

Beaker 1:

Radius (r₁) = 2 cm
Height (h₁) = 3 cm

Volume (V₁) = π r₁² h₁ = 3.14 x 2² x 3 = 37.68 cm³

Beaker 2:

Radius (r₂) = 6 cm
Height (h₂) = 4 cm
Volume (V₂) = π r₂² h₂ = 3.14 x 6² x 4 = 452.16 cm³

Volume of beaker = V₁ + V₂ = 37.68 + 452.16 = 489.84 cm³

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3 years ago

Read 2 more answers

im in third grade on my moms computer it says nico put some cuppcakes in the oven in 8:55 and takes them out 25 mintues when sho

nekit [7.7K]

He should take them out at 9:20.

Hope this helps!

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3 years ago