A. With the previous exercise we can deduce that there is the situation of a number of sales in a grocery store, the relative frequency for the number of units sold, is shown below:

units sold. relative frequency. Acumulative frequency. interval of random numbers

30. 0.16. 0.16. 0.00 <0.16

40. 0.24. 0.4. 0.16 <0.4

50. 0.3. 0.7. 0.4 <0.7

60. 0.2. 0.9. 0.7<09

70. 0.1. 1. 0.9<1

B. For the next point, they give us some random numbers and then it is compared with the simulation of 10 days in sales:

random Units

number. sold

0.12. 30

0.96. 70

0.53. 50

0.80. 60

0.95. 70

0.10. 30

0.40. 50

0.45. 50

0.77. 60

0.29. 40

the two lists are compared so that opposite each one is the result of the simulation

3 0

2 years ago

the probability that we encounter a green light at the corner of college and main is 0.35, a yellow light 0.04, and a red light

Ostrovityanka [42]

Answer:

21% probability you will hit a green light on monday and a red light on tuesday

Step-by-step explanation:

When two events, A and B, are independent, we have that:

$P(A \cap B) = P(A) \times P(B)$

In this problem, we have that:

Event A: Green light on monday.

Event B: Red light on tuesday.

The probability that we encounter a green light at the corner of college and main is 0.35

This means that $P(A) = 0.35$

The probability that we encounter a red light is 0.61:

This means that $P(B) = 0.61$

These events are independent, that is, the light color on Tuesday is independent of the color on Monday. So

$P(A \cap B) = P(A) \times P(B) = 0.35 \times 0.6 = 0.21$

21% probability you will hit a green light on monday and a red light on tuesday

8 0

3 years ago

To complete this component you will need to insert parentheses in Expression 2 to change the order of operations so the expressi

Alika [10]

Given:

The expression is $5+4\times 2+6-2\times 2-1$ .

To find:

The position of parentheses inserted in the expression to get the value 19

Step-by-step explanation:

We have,

$5+4\times 2+6-2\times 2-1$

Now,

$(5+4)\times 2+6-2\times 2-1=9\times 2+6-4-1$

$(5+4)\times 2+6-2\times 2-1=18+6-5$

$(5+4)\times 2+6-2\times 2-1=18+1$

$(5+4)\times 2+6-2\times 2-1=19$

There are more ways to apply the parenthesis, but we do not get 19.

$5+4*\left(2+6\right)-2*2-1=32\neq 19$

$5+4*2+\left(6-2\right)*2-1=20\neq 19$

$5+4*2+6-2*\left(2-1\right)=17\neq 19$

And many more possibilities.

Therefore, the expression after inserting the parentheses is $(5+4)\times 2+6-2\times 2-1$ .

6 0

2 years ago