A) The area of the rectangle ABCD is base times height. 20in x 12in = 240 in sq.
B) The area of the triangle AED is base times height divided by two. (14in x 12in)/2 = 84in sq.
C) Figure EBCD is a right trapezoid (having one pair of parallel sides, while the others are slanted and forming a right angle).
D) Area of EBCD is the area of the rectangle minus the area of the triangle. 240in sq - 84in sq = 156in sq.
If you havent learnt Sin, Cos yet, let me know, so we can try the other solutions.
First of all we can draw a parallel line to divide the figure into a triangle and a rectangle as shown in the figure. To find the area of our rectangle, remember that the area of a rectangle is length times width, so

. Since we know for our figure that the length and width of our rectangle are 13cm and 6cm respectively, lets replace those values in our formula to get its area:


Similarly, the area of a triangle is one half times base times height, so

. Since we know that our base is 8cm and our height 6cm, lets replace those values in our equation to find the area of our triangle:


Now the only thing left is add our areas:

We can conclude that the correct answer is <span>
A. 102</span>
False. Perpendicular lines run beside each other not through each other.
The average rate of change of <em>f(x)</em> on -3 ≤ <em>x</em> ≤ 3 is given to be
(<em>f</em> (3) - <em>f</em> (-3)) / (3 - (-3)) = -2.5
If <em>f</em> (-3) = 14, then
(<em>f</em> (3) - 14) / (3 + 3) = -2.5
(<em>f</em> (3) - 14) / 6 = -2.5
<em>f</em> (3) - 14 = -15
<em>f</em> (3) = -1