Question

Consider the differential equation: dy/dx = (y-2)(x^2+1)

Answer 1

Answer:

6

Step-by-step explanation:

Given,

$\dfrac{dy}{dx}=(y-2)(x^2+1)$ ...(i)

Differentiating w.r. to x.

$\dfrac{d^2y}{dx^2}= (y-2)(2x)+ (x^2+1)\dfrac{dy}{dx}$

From equation (1)

$\dfrac{d^2y}{dx^2}= (y-2)(2x)+ (x^2+1)^2(y-2)$

Now, at the point (1,3)

$\dfrac{d^2y}{dx^2}= (3-2)(2\times 1)+ (1^2+1)^2(3-2)$

$\dfrac{d^2y}{dx^2}=6$