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3 years ago

The sum of three and four tenths and a number is six and six tenths.

Mathematics

2 answers:

RUDIKE [14]3 years ago

7 0

Answer:

n=3.2

Step-by-step explanation:

Solnce55 [7]3 years ago

5 0

Hopefully I drew what you described.

The 6.6 represents the total of N + 3.4
We subtract the part we know from the whole /sum/total we know to get the other part.
So 6.6 - 3.4 = N
3.2 = N

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The length of a rectangle is 2 cm less than it’s width.If the area of the rectangle is 35 cm^2,find the width

Elan Coil [88]

Answer:

7cm

Step-by-step explanation:

Area = Length x width

A = 35

w= L - 2

L = w+ 2

Now it becomes

35 = ( w+2) x w

35 = w^2 + 2w

W^2 + 2w - 35 = 0

By Factorization we have

( w + 7)( w-5)

w = 5cm

Since L = w + 2, we have

L = 5 + 2

= 7cm

5 0

3 years ago

Now, lets evaluate the same integral using power series. first, find the power series for the function f(x = \frac{32}{x^2+4}. t

BlackZzzverrR [31]

No idea what the previous part of the problem is, but you have

$f(x)=\dfrac{32}{x^2+4}=\dfrac8{1-\left(-\frac{x^2}4\right)}=\displaystyle8\sum_{n\ge0}\left(-\frac{x^2}4\right)^n$
$f(x)=\displaystyle8\sum_{n\ge0}\left(-\dfrac14\right)^nx^{2n}$

which is valid for $\left|-\dfrac{x^2}4\right|$ , or $|x|$ . So the integral from 0 to 2 is

$\displaystyle\int_0^2f(x)\,\mathrm dx=\int_0^28\sum_{n\ge0}\left(-\frac14\right)^nx^{2n}\,\mathrm dx$
$=\displaystyle8\sum_{n\ge0}\left(-\frac14\right)^n\int_0^2x^{2n}\,\mathrm dx$

Note that since the power series only converges on the interval if $x$ is strictly less than 2, which means we have to treat this as an improper integral.

$=\displaystyle8\sum_{n\ge0}\left(-\frac14\right)^n\lim_{t\to2^-}\int_0^tx^{2n}\,\mathrm dx$ [/tex]
$=\displaystyle8\sum_{n\ge0}\left(-\frac14\right)^n\lim_{t\to2^-}\frac{x^{2n+1}}{2n+1}\bigg|_{x=0}^{x=t}$
$=\displaystyle8\sum_{n\ge0}\frac{(-1)^n}{2^{2n}(2n+1)}\lim_{t\to2^-}t^{2n+1}$
$=\displaystyle16\sum_{n\ge0}\frac{(-1)^n}{2n+1}$
$=16-\dfrac{16}3+\dfrac{16}5-\dfrac{16}7+\dfrac{16}9+\cdots$

6 0

3 years ago

N which number does the digit 5 have a value that is ten times greater than the value of the digit 5 in the number 245,093?

OLEGan [10]

Answer:

53,901

Step-by-step explanation:

Here is the complete question :

In which number does the digit 5 have a value that is ten times greater than the value of the digit 5 in the number 245,093?

43,567

45,248

53,901

562,011

In the number 245,093 :

3 = units

9 = tens

0 = hundred

5 = thousand

4 = ten thousand

2 = hundred thousand

the value of 5 in the number is 5000. the number that would have a value that it 10 times greater than 5 in 245,093 must occupy the value of ten thousand.

looking through the options, it is only in 53,901 that 5 occupies a value of ten thousand

6 0

3 years ago

An airplane 30000 feet above the ground begins descending at a rate of 2000 feet per minute The best form to use is because ther

mina [271]

Answer:

30000-2000=28000 feet.

This is a form of subtraction to use the ground and descend to ground level.

Step-by-step explanation:

4 0

3 years ago

The National Academies of Sciences Engineering, and Medicine

snow_tiger [21]

<em>Greetings from Brasil...</em>

According to the annex, we note that

1 qt = 1 quart = 0.95L

To solve this problem, just apply some rules of 3.....

1st - how many qt's are in 15.5 cups

qt cup

1 ---------- 4

X ---------- 15.5

4 · X = 1 · 15.5

4X = 15.5

X = 15.5 ÷ 4

X = 3.875qt

Last rule of 3 to know how many liters there are in 3.875qt:

qt litres

1 ---------- 0.95

3.875 ---------- Y

1 · Y = 0.95 · 3.875

In a day a young man should drink 3.68L of water

6 0

3 years ago