Answer:
Temperature of the air in the balloon = 272°C
Explanation:
Given:
Volume of balloon = 500 m³
Air temperature = 15° C = 273 + 15 = 288 K
Total weight = 290 kg
Density of air = 1.23 kg/m³
Find:
Temperature of the air in the balloon
Computation:
Density of hot air = Density of air - [Total weight / Volume of balloon]
Density of hot air = 1.23 - [290 - 500]
Density of hot air = 0.65 kg/m³
[Density of hot air][Temperature of the air in the balloon] = [Density of air][Air temperature ]
Temperature of the air in the balloon = [(1.23)(288)]/(0.65)
Temperature of the air in the balloon = 544.98
Temperature of the air in the balloon = 545 K
Temperature of the air in the balloon = 545 - 273 = 272°C
Answer:
2991.42 N
Explanation:
For this problem, we'll use the equations: momentum= mass x velocity and impulse = change in momentum, and impulse=force x time.
initial momentum; p1 = 0.17 x 41 = 6.97 kg.m/s
final momentum; p2 = 0, because final velocity is 0 m/s
Thus,
impulse = p1 - p2= 6.97 - 0 = 6.97 kg.m/s
Finally, impulse= Force x time,
Thus, Force = Impulse/time
Force= 6.97/ (2.33 x 10^(-3)) = 2991.42 N
Answer:
8.4335 x 10^-²¹, 1.78204 x 10²⁶
Explanation:
p = mv
p = (5.05 x 10⁶)(1.67 x 10^-²⁷)
p = 8.4335 x 10^-²¹
p = mv
p = (5.98 x 10²⁴)(2.98 x 10)
p = 1.78204 x 10²⁶
Answer:
The momentum makes it worse.
Explanation:
The momentum of vehicles running at faster speeds is very high and causes a lot of damage to the vehicles.