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belka [17]
3 years ago
12

A train travels at 100 km/h heading east to reach a town in 4 hours. The train then reversed ad heads west at 50 km/h for 4 hour

s
Physics
1 answer:
Phantasy [73]3 years ago
3 0
What’s something goes up but never comes down?
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A phone cord is 2.28 m long. The cord has a mass of 0.2 kg. A transverse wave pulse is produced by plucking one end of the taut
Debora [2.8K]

The characteristics of the speed of the traveling waves allows to find the result for the tension in the string is:  

         T = 10 N

The speed of a wave on a string is given by the relationship.

      v =\sqrt{\frac{T}{\mu } }

Where   v es the velocty, t is the tension ang μ is the lineal density.

They indicate that the length of the string is L = 2.28 m and the pulse makes 4 trips in a time of t = 0.849 s, since the speed of the pulse in the string is constant, we can use the uniform motion ratio, where the distance traveled e 4 L

           v = \frac{d}{t}  

           v = \frac{4 L}{t}  

           v = \frac{4 \ 2.28 }{0.849}  

            v = 10.7  m / s

Let's find the linear density of the string, which is the length of the mass divided by its mass.

            μ = \frac{m}{L}  

            \mu = \frac{0.2}{2.28}  

            μ = 8.77 10⁻² kg / m

The tension is:

        T = v² μ

Let's calculate

        T = 10.7²  8.77 10⁻²

        T = 1 0 N

In conclusion using the characteristics of the velocity of the traveling waves we can find the result for the tension in the string is:

         T = 10 N

Learn more here:  brainly.com/question/12545155

7 0
3 years ago
A spring has a 12 cm length. When a 200-g mass is hung from the spring, it extends to 27 cm. The hanging mass were pulled downwa
BartSMP [9]

Answer:

The equation of the time-dependent function of the position is x(t)=5\cos(8.08t)

(b) is correct option.

Explanation:

Given that,

Length = 12 cm

Mass = 200 g

Extend distance = 27 cm

Distance = 5 cm

Phase angle =0°

We need to calculate the spring constant

Using formula of restoring force

F=kx

mg=kx

k=\dfrac{mg}{x}

k=\dfrac{200\times10^{-3}\times9.8}{(27-12)\times10^{2}}

k=13.06\ N/m

We need to calculate the time period

Using formula of time period

T=2\pi\sqrt{\dfrac{m}{k}}

Put the value into the formula

T=2\pi\sqrt{\dfrac{0.2}{13.6}}

T=0.777\ sec

At t = 0, the maximum displacement was 5 cm

So, The equation of the time-dependent function of the position

x(t)=A\cos(\omega t)

Put the value into the formula

x(t)=5\cos(2\pi\times f\times t)

x(t)=5\cos(2\pi\times\dfrac{1}{T}\times t)

x(t)=5\cos(2\pi\times\dfrac{1}{0.777}\times t)

x(t)=5\cos(8.08t)

Hence, The equation of the time-dependent function of the position is x(t)=5\cos(8.08t)

8 0
3 years ago
What is one way wind or water change the earth?
insens350 [35]

Answer:

water hydrates the earth's soil....

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What is electrical energy​
Inga [223]

Answer:

Electric is produce by water it is very helpful in our life

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Bingel [31]

Answer:

It is experimental. She will testing or investigating on children. So yeah, it is experimental

7 0
3 years ago
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