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3 years ago

12

Translate the sentence into an equation.

1 answer:

coldgirl [10]3 years ago

7 0

Hey there!

We want to multiply a certain quantity by 2, so we will put the two outside of parentheses and put our variable (x) minus two inside the parentheses to represent this. This will all equal two.

2(x-6)=2

The unknown number is also 7.

I hope that this helps!

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How do i graph 2y=1/2x+10 using slope intercept form

sergij07 [2.7K]

2y=1/2x+10
divide by two
y=1/4x+5

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3 years ago

State a reason why a number does not belong with the others. <br> 32 64<br> 81 144

KiRa [710]

Answer : 81 because it is the only one that is not a multiple of 4

Step-by-step explanation:

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3 years ago

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Can someone please help me with this.

allsm [11]

Answer:

10

Step-by-step explanation:

Given expression is $|8-6 i|$ .

$|8-6 i|$ is a complex expression.

The value of<em> i </em>is –1.

By definition of absolute value, $|a+b i|=\sqrt{a^{2}+b^{2}}$

Now, substitute $|8-6 i|$ in the above formula.

$\Rightarrow|8-6 i|=\sqrt{8^{2}+(-6)^{2}}$ (since <em>i </em>= –1)

$=\sqrt{64+36}$ (since $8^{2}=64$ and $–6^{2}=36$ )

$=\sqrt{100}$ (Square root of 100 is 10)

= 10

Hence, the value of the expression $|8-6 i|$ is 10.

3 0

3 years ago

You deposit $300 in a savings account that pays 6% interest compounded semiannually. How much will you have at the middle of the

Otrada [13]

Answer:

Please check the explanation.

Step-by-step explanation:

a) How much will you have at the middle of the first year?

Principle P = $300

Annual rate r = 6% = 0.06 per year

Compound n = Semi-Annually = 2

Time (t in years) = 0.5 years

Total amount = A = ?

Using the formula

$A\:=\:P\left(1+\frac{r}{n}\right)^{nt}$

substituting the values

$A=300\left(1+\frac{0.06}{2}\right)^{\left(2\right)\left(0.5\right)}$

$A=300\cdot \frac{2.06}{2}$

$A=\frac{618}{2}$

$A=309$ $

Therefore, the total amount accrued, principal plus interest, from compound interest on an original principal of $ 300.00 at a rate of 6% per year compounded 2 times per year over 0.5 years is $ 309.00.

Part b) How much at the end of one year?

Principle P = $300

Annual rate r = 6% = 0.06 per year

Compound n = Semi-Annually = 2

Time (t in years) = 1 years

Total amount = A = ?

Using the formula

$A\:=\:P\left(1+\frac{r}{n}\right)^{nt}$

so substituting the values

$A\:=\:300\left(1+\frac{0.06}{2}\right)^{\left(2\right)\left(1\right)}$

$A=300\cdot \frac{2.06^2}{2^2}$

$A=318.27$ $

Therefore, the total amount accrued, principal plus interest, from compound interest on an original principal of $ 300.00 at a rate of 6% per year compounded 2 times per year over 1 year is $ 318.27.

7 0

3 years ago

50 PTS ANSWER ALL <3333333

11Alexandr11 [23.1K]

QUESTION 33

The length of the legs of the right triangle are given as,

6 centimeters and 8 centimeters.

The length of the hypotenuse can be found using the Pythagoras Theorem.

${h}^{2} = {6}^{2} + {8}^{2}$

${h}^{2} = 36+ 64$

${h}^{2} = 100$

$h = \sqrt{100}$

$h = 10cm$

Answer: C

QUESTION 34

The triangle has a hypotenuse of length, 55 inches and a leg of 33 inches.

The length of the other leg can be found using the Pythagoras Theorem,

${l}^{2} + {33}^{2} = {55}^{2}$

${l}^{2} = {55}^{2} - {33}^{2}$

${l}^{2} = 1936$

$l = \sqrt{1936}$

$l = 44cm$

Answer:B

QUESTION 35.

We want to find the distance between,

(2,-1) and (-1,3).

Recall the distance formula,

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Substitute the values to get,

$d=\sqrt{( - 1-2)^2+(3- - 1)^2}$

$d=\sqrt{( - 3)^2+(4)^2}$

$d=\sqrt{9+16}$

$d=\sqrt{25}$

$d = 5$

Answer: 5 units.

QUESTION 36

We want to find the distance between,

(2,2) and (-3,-3).

We use the distance formula again,

$d=\sqrt{( - 3-2)^2+( - 3- 2)^2}$

$d=\sqrt{( - 5)^2+( - 5)^2}$

$d=\sqrt{25+25}$

$d=\sqrt{50}$

$d=5\sqrt{2}$

Answer: D

8 0

3 years ago

Read 2 more answers