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3 years ago

N = x + y - n = 5 and part two x = u + v = o whats the answer?

1 answer:

Colt1911 [192]3 years ago

8 0

Just substitute the value of x from second equation into first equation:
N = x + y - n = 5
N = u + v + y - n = 5
N = 0 + y - n = 5

In short, N would be equal to y - n which is still equal to 5

Hope this helps!

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Wendy is creating a large soup based on a recipe. Her recipe calls for of a pint of milk, but she only has of a pint of milk, so

xeze [42]

Answer:

She can only make 5/6 of her recipe with the amount of milk that she has.

Step-by-step explanation:

Some data of this problem is missing, the data missing is:

Her recipe calls for 3/4 of a pint of milk and she only has 5/8 of a pint of milk.

Now, to know what's the portion she can do with that amount we need to divide the amount of milk she has by the total amount she needs:

$\frac{5}{8}$ ÷ $\frac{3}{4}$

When we divide we turn the second fraction upside down (the numerator becomes the denominator and viceversa) and multiply, thus:

$\frac{5}{8}$ ÷ $\frac{3}{4}=\frac{5}{8}$ × $\frac{4}{3} =\frac{20}{24}$

If we simplify this last expression we have:

$\frac{20}{24}=\frac{10}{12} =\frac{5}{6}$

Thus, she can only make 5/6 of her recipe with the amount of milk that she has.

<em>Note: In case the data missing is different, you can apply this same procedure with the fractions you have. </em>

6 0

4 years ago

Help i need the answer idk what or how to do this

natta225 [31]

14^(7x) = 17^(-8-x)

Take the log of both sides:

7x*log 14 = -(8+x)*log 17, or 7x^log 14 = -8*log 17 - x*log 17.

Grouping the x terms, we get x(7*log 14 + log 17)= -8*log 17

Then:
-8*log 17
x= -------------------------- (answer)
7*log 14 + log 17

6 0

3 years ago

Quadrilateral ABCD is a rhombus with an area of 20 square inches.

Ugo [173]

Answer:

area of rhombus =1/2 d1×d2

20=1/2 ×10×d2

d2=4

intersection of diagonal make right angle and cut in equal parts

d1/2=10/2=5

d2/2=4/2=2

use Pythagoras in right angle to bide side

side^2= 5^2 +2^2

side = √29

8 0

3 years ago

If eight trash bags last for thirty days then how many trash bags do you need for 180 days

34kurt

Let's Just See How Many Times 30 Goes Into 180

$\frac{180}{30} = 6$
Since 8 trash bags last 30 days, let's multiply

$6 \times 8 = 48 \: bags$
ANSWER

You'll Need 48 Trash Bags For 180 Days

5 0

3 years ago

Read 2 more answers

Please no links because they dont work :).

mr_godi [17]

Answer:

semoga jawapan ini dapat membantu

6 0

3 years ago