Answer:
Initial speed u = 29.94 m/s or 98.23 ft/s
Maximum height h = 22.87m or 75.03ft
Step-by-step explanation:
The range of a projectile is the horizontal distance covered by the projectile. And can be written as;
Range R = u^2sin2θ/g
Given:
R = 300 ft = 91.44 m
Angle θ = 45°
u = initial speed
g = acceleration due to gravity = 9.8m/s^2
u^2 = Rg/sin2θ
u = √(Rg/sin2θ)
u = √(91.44×9.8/sin(2×45))
u = 29.94 m/s or 98.23 ft/s
The maximum height can be derived from
h = u²sin²θ/2g
Substituting the values.
h = (29.94)^2 × sin²(45) / (2×9.8)
h = 22.87m or 75.03ft