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slava [35]
3 years ago
13

A six-sided dice is thrown once

Mathematics
2 answers:
g100num [7]3 years ago
8 0
A : 1/6 is the answer hope it helps
Keith_Richards [23]3 years ago
6 0

\frac{1}{6}

There are 6 sides in a cube and each side has a different number so you're chance of getting a 3 is 1/6.

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What is the sum of the series? Write in expanded form making sure to show all steps used to find the sum
pantera1 [17]

Answer:

-16

Step-by-step explanation:

k = 3

-2(3) + 5 = -1

k = 4

-2(4) + 5 = -3

k = 5

-2(5) + 5 = -5

k = 6

-2(6) + 5 = -7

(-1) + (-3) + (-5) + (-7)

= -16

3 0
2 years ago
Read 2 more answers
A right triangle has side lengths 4 units, 5 units, and x units what is the difference between the difference values of x?
irina [24]

Use the Pythagorean theorem.

If x is a hypotenuse, then we have:

x^2=4^2+5^2\\\\x^2=16+25\\\\x^2=41\to x=\sqrt{41}

If x is a leg, then we have:

x^2+4^2=5^2\\\\x^2+16=25\ \ \ \ |-16\\\\x^2=9\to x=\sqrt9\to x=3

Answer: \sqrt{41}-3

6 0
3 years ago
Multiply. Do not round your answer.<br> 9.2 x 14.71 =
Rzqust [24]
135.33 I didn’t round
7 0
1 year ago
In each of the following word problems, the question is missing. Write a possible question for each word problem.
garik1379 [7]

The question that can complete the given word problem is, The material comes in pieces of 5 years each. <em>How many </em><em>pieces</em><em> of </em><em>materials </em><em>are needed to </em><em>make a coat</em><em>?</em>

<h3>What question can be formed?</h3><h3 />

You are given the number of yards that are needed to make a coat so the question should be centered around that.

Questions that go best with such information are those that have to do with solving for the number of materials that would be needed to make the coat.

You can therefore supply the length of each piece of material, and then find out how many materials would then be needed to make a coat.

Find out more on formulating questions at brainly.com/question/11876376.

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4 0
1 year ago
Solve using the Quadratic Formula: 3x2 + 3x - 6 - 0 -2, 1 1, 2 -3, 9 -3, -9
AysviL [449]
Assuming that the equation is 3x^2+3x-6=0, then use the quadratic equation, (-b+- sqrt(b^2-4ac))/2a, with ax^2+bx+c as the original equation. so here we get (-3+-sqrt(9+72))/6 = (-3+-sqrt(81))/6 = (-3+-9)/6, = (-1+-3)/2 = 1 or -2. Plug in original to check.
6 0
3 years ago
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