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skad [1K]
3 years ago
6

An international company has 26,900 employees in one country. If this represents 16.9% of the company's employees, how many empl

oyees does it have in total?
Mathematics
1 answer:
Ad libitum [116K]3 years ago
6 0
Let's say they have "x" employees in total, so, that's the 100% of their workforce.

now, if we take "x" to be the 100%, and we know 26900 is 16.9%, what the dickens is "x" anyway?

\bf \begin{array}{ccll}
amount&\%\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
x&100\\
26900&16.9
\end{array}\implies \cfrac{x}{26900}=\cfrac{100}{16.9}\implies x=\cfrac{26900\cdot 100}{16.9}

now, you get a decimal figure, I take you need to round it up to a whole number.

the decimal result is likely due to any rounding up done to the 16.9.
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4 0
1 year ago
Assume that different groups of couples use the XSORT method of gender selection and each couple gives birth to one baby. The XS
olganol [36]

Answer:

Mean and Standard deviation for the numbers of girls in groups of 36 births are 18 and 3 respectively.

Step-by-step explanation:

We are given that he X SORT method is designed to increase the likelihood that a baby will be a girl, but assume that the method has no effect, so the probability of a girl is 0.5.

Now consider a group consisting of 36 couples.

The above situation can be represented through binomial distribution;

P(X=r)=\binom{n}{r} \times p^{r} \times (1-p)^{n-r} ;x=0,1,2,3,.....

where, n = number of trials (samples) taken = 36 couples

            r = number of success

            p = probability of success which in our question is probability

                   of a girl, i.e.; p = 0.5

<em><u>Let X = Numbers of girls in groups of 36 births </u></em>

So, X ~ Binom(n = 36, p = 0.5)

Now, mean for the numbers of girls in groups of 36 births is given by;

         <u>Mean</u>, E(X) = n \times p = 36 \times 0.5 = 18

Also, standard deviation for the numbers of girls in groups of 36 births is given by;

        <u>Standard deviation</u>, S.D.(X) =  \sqrt{n\times p\times (1-p)}

                                                      =  \sqrt{36\times 0.5\times (1-0.5)}

                                                      =  3

3 0
3 years ago
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