Answer:
Step-by-step explanation:
I have 30 coins, all nickels, dimes, and quarters, worth $4.60. There are two more dimes than quarters. How many of each kind of coin do I have.
..
let quarters be x
dimes = x+2
...
dimes + quarters = x+x+2=2x+2
...
nickels = 30-(2x+2)
...
5(30-(2x+2))+10(x+2)+25x=460
5(30-2x-2)+10x+20+25x=460
150-10x-10+10x+20+25x=460
160+25x=460
-160
25x=460-160
25x=300
/25
x=300/25
x=12 ---- quarters
x+2= 12+2=14 dimes
30-(2x+2)=4 nickels
...
check
4*5+14*10+12*25=20+140+300=460
Answer:
20
Step-by-step explanation:
First, let's find how much she spent on the expensive calculators
40 times $16400= $656,000
Now, lets find how much money she had for the cheap calculators.
$774,000- $656,000=$118000
Now that we have her budget (money remaining) for the cheaper calculators, lets divide that by the price for each individual calculator.
$118000/$5900=20
If you like my answer, please mark me as a brainliest! (I am new to this community.)
The opposite would be 3
__
4
Just switch out the negatives for positives
