They will continue moving because an object in motion will stay in motion until acted upon by a new force. I believe this is Newton's Law of Motion.
1.062 mol/kg.
<em>Step 1</em>. Write the balanced equation for the neutralization.
MM = 204.22 40.00
KHC8H4O4 + NaOH → KNaC8H4O4 + H2O
<em>Step 2</em>. Calculate the moles of potassium hydrogen phthalate (KHP)
Moles of KHP = 824 mg KHP × (1 mmol KHP/204.22 mg KHP)
= 4.035 mmol KHP
<em>Step 3</em>. Calculate the moles of NaOH
Moles of NaOH = 4.035 mmol KHP × (1 mmol NaOH/(1 mmol KHP)
= 4.035 mmol NaOH
<em>Step 4</em>. Calculate the mass of the NaOH
Mass of NaOH = 4.035 mmol NaOH × (40.00 mg NaOH/1 mmol NaOH)
= 161 mg NaOH
<em>Step 5</em>. Calculate the mass of the water
Mass of water = mass of solution – mass of NaOH = 38.134 g - 0.161 g
= 37.973 g
<em>Step 6</em>. Calculate the molal concentration of the NaOH
<em>b</em> = moles of NaOH/kg of water = 0.040 35 mol/0.037 973 kg = 1.062 mol/kg
The answer is: "barometer" .
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Answer:
d. HNNH has both the strongest nitrogen-nitrogen bond and the shorter nitrogen-nitrogen bond.
Explanation:
The Lewis structure of HNNH comprises of a double bound between the two nitrogen atoms, therefore each nitrogen still carrying a lone pair of electron and a single bond between each nitrogen to it respective hydrogen.
Also for H_2NNH_2; there exists a single nitrogen to nitrogen bond because hydrogen is sharing two bonds already with the nitrogen; the nitrogen also possess a lone pair of electron and the last bond is a single bond between the nitrogen to nitrogen atom ( therefore obeying the octet rule).
The bond strength and bond angle is stronger and shorter in double bonds than single bonds, thus HNNH has both the strongest nitrogen-nitrogen bond and the shorter nitrogen-nitrogen bond.
Answer:
Approximately 241 kJ/mol reaction.
Explanation:
How many moles of the reaction took place?
The coefficient in front of both NaOH and HCl are both one. In other words, one mole of the reaction will require one mole of NaOH and one mole and HCl.
of both NaOH and HCl are available. As a result, 0.0025 moles of the reaction would have taken place.
How much heat was produced?
Approximate volume of the solution:
.
Approximate mass of the solution:
.
Enthalpy change per mole reaction:
.
