Answer:
F = 263.51 N
Explanation:
given,
diameter of wheel = 78 cm
diameter of axle = 14.8 cm
Force exerted on the rim of wheel = 150 N
Force applied outside the axle = ?
To prevent rotation wheel from rotating the Force 'F' should be applied outside of the axle.
Net momentum about the center of mass should be zero
now,
Moment of about center due to 150 N = moment about center due to F on axle
7.4 F = 1950
F = 263.51 N
Hence, Force exerted outside of the axle in order to prevent the wheel from rotating is equal to 263.51 N.
It depends, one can be darker or lighter. There can be many colors of shade, there can also be different patterns of shade.
Opposite force in the opposite.
<span>To answer this question, the equation that we will be using is:
y = A cos bx + c
where A = amplitude, b = 2 pi/Period, Period = 12 hrs, c = midline,
x = t and y = f(t)
A = 1/2 (Xmax - Xmin)
12 - 2 / 2 = 10/2 = 5
b = 2 pi / 12 = pi/6
c = 1/2 (Xmax + Xmin)
12+2/2 = 7
answer: f(t) = 5 cos pi/6 t + 7 </span>
Answer:
size of popcorn seed may meet the scaled earth size of x = 0.07312 in.
Explanation:
Given:-
- The diameter of actual sun, Ds = 1.3927 * 10^6 km
- The diameter of model sun ball, ds = 8 in
- The diameter of the actual earth, De = 12,742 km
Find:-
How large would be the earth model
Solution:-
- We can use the actual diameters of the earth and sun to develop the ratio of earth diameter to that of sun. The direct ratio can be used to model the diameter of earth for the scale model
Sun Earth
Actual : 1392700 km 12,742 km
Scale : 8 in x
- Use direct relations and solve for x:
x = (8 in)*(12,742 km ) / ( 1392700 km )
x = 0.07312 in.
- From the given options apple, grapefruit and marble diameters are larger than 1 inch. So only the size of popcorn seed may meet the scaled earth size of x = 0.07312 in.