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igomit [66]
3 years ago
9

When two air masses with different pressure collide,What weather event are we most likely to experience

Physics
1 answer:
Scilla [17]3 years ago
5 0

You would experience stormy and unsettled weather

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A hockey puck is hit so that it leaves the stick at 50.4m/s. If it takes 0.25 s for the puck to hit the boards, how far is the p
notka56 [123]
Speed = 50.4 m/s
Time = 0.25 s

Distance  =  (speed) x (time)  =  (50.4 m/s) x (0.25 s)  =  12.6 meters.
3 0
3 years ago
The rate of distance traveled per unit of time, without regard to direction
masya89 [10]

Answer: Speed

Explanation:

The speed of a body is the rate of distance (in metres) that it travels in one second. Hence, speed unlike velocity, is total distance travelled by the body without regard to direction divided by the total time taken.

i.e Speed = Distance / time taken

Thus, the standard international (SI) unit of speed is metres per second (m/s)

6 0
4 years ago
Read 2 more answers
Suppose a radio signal (light) travels from Earth and through space at a speed of 3 × 108/ (this is the speed of light in vacuum
Umnica [9.8K]

Answer:

18*10^10 meters

Explanation:

V= d/t         10 mins = 600 seconds

3*10^8 = d/600s

(3*10^8)*(6*10^2) = d

d = 18*10^10 m

6 0
4 years ago
What is f if you have an object 2.0 m from the concave mirror, and the image is 4.0 m from the mirror?
dezoksy [38]

Answer:

the f is 1.3 m

Explanation:

Given that

An object 2.0m is from the concave mirror

And, the image is 4.0m from the mirror

We need to find out the f

So,

u = -2 m

v = -4 m

1 ÷ f = 1 ÷ v + 1 ÷ u

= (-1 ÷ 4) + (-1 ÷ 2)

= -3 ÷4

f = -4 ÷ 3

= |1.3| m

Hence, the f is 1.3 m

7 0
3 years ago
Suppose you have two small pith balls that are 5.5 cm apart and have equal charges of -29 nc?
zysi [14]
The question is missing, however, I guess the problem is asking for the value of the force acting between the two balls.

The Coulomb force between the two balls is:
F= k_e \frac{ q_1 q_2}{r^2}
where k_e=8.99\cdot10^9~N m^2 C^{-2} is the Coulomb's constant, q_1=q_2=29~nC=29\cdot 10^{-9}~C is the intensity of the two charges, and r=5.5~cm=0.055~m is the distance between them.

Substituting these numbers into the equation, we get
F=2.5~10^{-3}~N

The force is repulsive, because the charges have same sign and so they repel each other.
6 0
3 years ago
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