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podryga [215]
3 years ago
10

Your uncle is in the below-deck galley of his boat while you are spear fishing in the water nearby. An errant spear makes a smal

l hole in the boat's hull, and water starts to leak into the galley. If the hole is 0.900 m below the water surface and has area 1.30 cm2 , how long does it take 10.0 L of water to leak into the boat?
Physics
1 answer:
attashe74 [19]3 years ago
6 0

Answer:18.31 s

Explanation:

Given

hole is h=0.9 m below the water surface

area of of hole A=1.30 cm^2

Q=10 L

velocity of Flow

v=\sqrt{2gh}

v=\sqrt{2\times 9.8\times 0.9}

v=\sqrt{17.64}

v=4.2 m/s

Rate of flow is given by

\dot{Q}=A\cdot v

\frac{Q}{t}=A\cdot v

\frac{10\times 10^{-3}}{t}=1.30\times 10^{-4}\cdot 4.2

t=\frac{10\times 10}{5.46}

t=18.31 s                              

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Answer:

C

Explanation:

gravity is a pulling force according to Newton

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If the mass of an object is 35kg on venus what is its mass on the sun
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Answer:

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If you ride your bike at an average speed of 2 km/h and need to travel a total distance of 20 km, how long will it take you to r
love history [14]

Answer:

Time taken to reach your destination will be 10hours

Explanation:

Recall the formula for Speed;

speed=Total distance/Total time taken

Speed=2km/h

Total distance=20km

Time taken=x

let x be the unknown time taken

Input each values into the formula;

2=20/x

Making x subject of the equation

x=20/2

x=10

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3 0
3 years ago
Read 2 more answers
A wave has a wavelength of 8 mm and a frequency of 14 Hertz what is its speed?
iren [92.7K]
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6 0
4 years ago
Ezra (m = 20.0 kg) has a tire swing and wants to swing as high as possible. He thinks that his best option is to run as fast as
Dmitriy789 [7]

Answer:

a) v=5.6725\,m.s^{-1}

b) h= 1.6420\,m

Explanation:

Given:

  • mass of the body, M=20\,kg
  • mass of the tyre,m=10\,kg
  • length of hanging of tyre, l=3.5m
  • distance run by the body, d=10m
  • acceleration of the body, a=3.62m.s^{-2}

(a)

Using the equation of motion :

v^2=u^2+2a.d..............................(1)

where:

v=final velocity of the body

u=initial velocity of the body

here, since the body starts from rest state:

u=0m.s^{-1}

putting the values in eq. (1)

v^2=0^2+2\times 3.62 \times 10

v=8.5088\,m.s^{-1}

Now, the momentum of the body just before the jump onto the tyre will be:

p=M.v

p=20\times 8.5088

p=170.1764\,kg.m.s^{-1}

Now using the conservation on momentum, the momentum just before climbing on the tyre will be equal to the momentum just after climbing on it.

(M+m)\times v'=p

(20+10)\times v'=170.1764

v'=5.6725\,m.s^{-1}

(b)

Now, from the case of a swinging pendulum we know that the kinetic energy which is maximum at the vertical position of the pendulum gets completely converted into the potential energy at the maximum height.

So,

\frac{1}{2} (M+m).v'^2=(M+m).g.h

\frac{1}{2} (20+10)\times 5.6725^2=(20+10)\times 9.8\times h

h\approx 1.6420\,m

above the normal hanging position.

3 0
3 years ago
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