Suppose you have two small pith balls that are 5.5 cm apart and have equal charges of -29 nc?
1 answer:
The question is missing, however, I guess the problem is asking for the value of the force acting between the two balls.
The Coulomb force between the two balls is:
where
is the Coulomb's constant, 
is the intensity of the two charges, and 
is the distance between them.
Substituting these numbers into the equation, we get
The force is repulsive, because the charges have same sign and so they repel each other.
The Coulomb force between the two balls is:
where
Substituting these numbers into the equation, we get
The force is repulsive, because the charges have same sign and so they repel each other.
You might be interested in
Explanation:
PRIMERO ENCUENTRAS EL PESO DEL PARACAIDISTA
= 65 kg(
) = 637 N
CON LA FÓRMULA DE LA ENERGÍA POTENCIAL
U = 637 N(6000 m - 3500 m) = 1592500 J
The concept required to solve this problem is associated with potential energy. Recall that potential energy is defined as the product between mass, gravity, and change in height. Mathematically it can be described as
Here,
= Change in height
m = mass of super heroine
g = Acceleration due to gravity
The change in height will be,
The final position of the heroin is below the ground level,
The initial height will be the zero point of our system of reference,
Replacing all this values we have,
Since the final position of the heroine is located below the ground, there will net loss of gravitational potential energy of 10744.81J