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prisoha [69]
2 years ago
13

Suppose you have two small pith balls that are 5.5 cm apart and have equal charges of -29 nc?

Physics
1 answer:
zysi [14]2 years ago
6 0
The question is missing, however, I guess the problem is asking for the value of the force acting between the two balls.

The Coulomb force between the two balls is:
F= k_e \frac{ q_1 q_2}{r^2}
where k_e=8.99\cdot10^9~N m^2 C^{-2} is the Coulomb's constant, q_1=q_2=29~nC=29\cdot 10^{-9}~C is the intensity of the two charges, and r=5.5~cm=0.055~m is the distance between them.

Substituting these numbers into the equation, we get
F=2.5~10^{-3}~N

The force is repulsive, because the charges have same sign and so they repel each other.
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insens350 [35]

Answer:

774.8 secs

Explanation:

distance(d)= speed(v)* time(t)

calculate speed:

refractive index = speed of light (c)/ speed of light in medium (v)

1.56 = 3*10^8*v

v=192307692.3 m/s

d = v *t

t = d/v

on substituting values:

t = 774.8 secs

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2 years ago
The Milky Way Galaxy is (a) another name for our solar system; (b) a small group of stars visible in our night sky; (c) a collec
gtnhenbr [62]

Answer:

C

Explanation:

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2 years ago
8. Contrast. The energy that can be released during a nuclear fission reaction with the energy that can be released during a nuc
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11)You need high temperatures for fusion because you're trying to push two atoms together (to "fuse" them as the name suggests)  The electrons in one atom repel the other electrons in the other atoms.  When stripped down to only protons, you still have to overcome this repulsion (Coulomb repulsion).  High temperatures means high velocity of the particles in the plasma.  This gives them enough "oomph" to get close enough to fuse.  Once close enough to each other, the nuclear force takes over and overwhelms the Coulomb repulsion and the nuclei fuse and release energy in doing so.
7 0
2 years ago
If a ball speeds up as it is rolling down a hill, the forces acting on it must be -
VMariaS [17]

Answer:

the forces acting on it must be strong because gravity is pushing the ball down

Explanation:

3 0
2 years ago
A student, who weighs 720N, is standing on a bathroom scale and riding an elevator that is moving downwards with a speed that is
jasenka [17]

Answer:

1) The mass of the student is approximately 73.39 kg

2) The net force on the student is approximately 947.523 N

3) The value the scale will read is approximately 96.59 kg

Explanation:

The given parameters are;

The weight of the student = 720 N

The speed at which the elevator is decreasing = 3.1 m/s²

1) The weight of the student = The mass of the student × The acceleration due to gravity

The acceleration due to gravity is a constant = 9.81 m/s²

Substituting the known values gives;

720 N = The mass of the student × 9.81 m/s²

∴ The mass of the student = 720 N/(9.81 m/s²) ≈ 73.39 kg

2) The forces acting on the student are;

i) The force of gravity which is the weight of the student acting downwards

ii) The inertia force of the slowing elevator acting downwards in the same direction as the weight of the student

The net force, F_{net} = The weight of the student + The inertia force of the slowing elevator

∴ The net force, F_{net} = 720 N + 73.39 kg × 3.1 m/s² ≈ 947.523 N

3) The scale will read the mass of the student as follows;

Mass reading of student on the scale = Force on scale/9.81

∴ Mass reading of student on the scale = 947.523/9.81 ≈ 96.59 kg

The value the scale will read = 96.59 kg.

3 0
3 years ago
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