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padilas [110]
3 years ago
5

When sitting in the tree the cat has a total of 1375J in its Gravitational potential store. What is the maximum amount of energy

that can be transferred when the cat lands on the ground?
Physics
1 answer:
Murrr4er [49]3 years ago
4 0

Answer:

1375J

Explanation:

The gravitational potential/potential energy of the at the top of the tree which is the energy by virtue of its position.

P.E = mgh

mass = m

Acceleration due to gravity = g

height = h

At the top of the tree, the value of h (height) is high resulting in the gravitational potential. When the cat lands on the ground, the value of h is zero, the the gravitational potential would be zero and all the potential energy have been converted to other forms of energy.

Therefore, the total gravitational potential store is equal to the maximum amount of energy that can be transferred which is equal to 1375J.

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Given parameters:

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Unknown:

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Here we use positive value of acceleration due to gravity because the coin is falling with the effect of acceleration and not against it.

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