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Arturiano [62]
3 years ago
7

Quadrilateral ABCD is inscribed in circle Pas shown. Which statement is necessarily true?

Mathematics
1 answer:
Svetradugi [14.3K]3 years ago
5 0

Given:

Quadrilateral ABCD is inscribed in a circle P.

To find:

Which statement is necessarily true.

Solution:

Quadrilateral ABCD is inscribed in a circle P.

Therefore ABCD is a cyclic quadrilateral.

In cyclic quadrilateral, opposite angles form a supplementary angles.

⇒ m∠A + m∠C = 180° --------- (1)

⇒ m∠B + m∠D = 180° --------- (2)

By (1) and (2),

⇒ m∠A + m∠C = m∠B + m∠D

This statement is necessarily true for the quadrilateral ABCD in circle P.

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2 years ago
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sergiy2304 [10]

Answer:

Part a) Option d

Part b) Option a

Step-by-step explanation:

Part a

if we look at the options given and the data available

Option a) x^4+9

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Putting x= 3 we get (3^4) + 9 =90 but f(x) =125 so not correct option

Option b) (4^x)+9

Putting x= 2 we get (4^2) + 9 =25

Putting x= 3 we get (4^3) + 9 =73 but f(x) =125 so not correct option

Option c) x^5

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Option d) 5^x

Putting x= 2 we get (5^2)  =25

Putting x= 3 we get (5^3)  =125

Putting x= 4 we get (5^4)  =625

So Option d is correct.

Part (b)

3(2)^3x

can be solved as:

=3(2^3)^x

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