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2 years ago

8

What does the domain mean for this problem?

1 answer:

irga5000 [103]2 years ago

3 0

Answer:

what problem?

Step-by-step explanation:

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Solve for x: 4 over x plus 4 over quantity x squared minus 9 equals 3 over quantity x minus 3. (2 points) Select one: a. x = -4

Kay [80]

Answer:

<h2>c. x = -4 or x = 9</h2>

Step-by-step explanation:

$\dfrac{4}{x}+\dfrac{4}{x^2-9}=\dfrac{3}{x-3}$

Domain:

$x\neq0\ \wedge\ x^2-9\neq0\ \wedge\ x-3\neq0\\\\x\neq0\ \wedge\ x\neq\pm3$

solution:

$\dfrac{4}{x}+\dfrac{4}{x^2-3^2}=\dfrac{3}{x-3}$

use <em>(a - b)(a + b) = a² - b²</em>

$\dfrac{4}{x}+\dfrac{4}{(x-3)(x+3)}=\dfrac{3}{x-3}$

multiply both sides by (x - 3) ≠ 0

$\dfrac{4(x-3)}{x}+\dfrac{4(x-3)}{(x-3)(x+3)}=\dfrac{3(x-3)}{x-3}$

cancel (x - 3)

$\dfrac{4(x-3)}{x}+\dfrac{4}{x+3}=3$

subtract $\frac{4(x-3)}{x}$ from both sides

$\dfrac{4}{x+3}=3-\dfrac{4(x-3)}{x}\\\\\dfrac{4}{x+3}=\dfrac{3x}{x}-\dfrac{(4)(x)+(4)(-3)}{x}\\\\\dfrac{4}{x+3}=\dfrac{3x-\bigg(4x-12\bigg)}{x}\\\\\dfrac{4}{x+3}=\dfrac{3x-4x-(-12)}{x}\\\\\dfrac{4}{x+3}=\dfrac{-x+12}{x}$

cross multiply

$(4)(x)=(x+3)(-x+12)$

use FOIL

$4x=(x)(-x)+(x)(12)+(3)(-x)+(3)(12)\\\\4x=-x^2+12x-3x+36$

subtract 4x from both sides

$0=-x^2+12x-3x+36-4x$

combine like terms

$0=-x^2+(12x-3x-4x)+36\\\\0=-x^2+5x+36$

change the signs

$x^2-5x-36=0\\\\x^2-9x+4x-36=0\\\\x(x-9)+4(x-9)=0\\\\(x-9)(x+4)=0$

The product is 0 if one of the factors is 0. Therefore:

$x-9=0\ \vee\ x+4=0$

$x-9=0$ <em>add 9 to both sides</em>

$x=9\in D$

$x+4=0$ <em>subtract 4 from both sides</em>

$x=-4\in D$

7 0

2 years ago

What is the surface area of the rectangular prism?<br> lenth 16 with 4 and hight 4

Llana [10]

Answer:

272

Step-by-step explanation:

The formula is 2(LxW) + 2(LxH) + 2(WxH)

2(16 x 4) = 128

2(16 x 4) = 128

2(4 x 4) = 16

16 + 128 + 128 = 272

5 0

2 years ago

If x = 3 /4 and y = 8, consider the sum of x and y. Which statement describes the sum of x and y? A) The sum of x and y is a rat

maksim [4K]

Answer: A is the correct one

4 0

2 years ago

That picture is another question

erastovalidia [21]

Answer:

1. 3.82 miles

i dont have 2

3. 31

Step-by-step explanation:

5 0

2 years ago

Solve for x. Show all your work

olasank [31]

42°

Step-by-step explanation:

$\angle BAE =180\degree -132\degree$

(Angles in linear pair)

$\angle BAE =48\degree$

$\angle AEB =90\degree..(\because \overrightarrow{EC}\perp\overrightarrow{ED})$

$\angle ABE = 180\degree-(48\degree+90\degree)$

(Angle sum postulate of a triangle)

$\implies\angle ABE = 180\degree-138\degree$

$\implies\angle ABE = 42\degree$

$\angle CDE =\angle ABE = 42\degree$

(corresponding angles)

$\implies x\degree=\angle CDE$

(vertical angles)

$\implies x\degree=42\degree$

$\implies x=42$

3 0

1 year ago