Answer:
No ABC is not a triangle
Step-by-step explanation:
Perimeter = 22 cm
AB = 8 cm ; BC = 8 cm
AC = 22 - ( 8 + 8 ) = 6 cm
But all those sides doesn't follow Pythagorean Theorem(AB^2 + BC^2 = AC^2) ....because 8^2 + 8^2 isn't equal to 6^2 ......
Had it followed the theorem , it could have been a right angle triangle...
Answer:
eleven below zero
Step-by-step explanation:
opposite of -11 =11 so that doesn't work
positive eleven=11 so that doesn't work
eleven greater than zero=11 so that doesn't work
eleven below zer0= -11 so it works
Answer:
Part 1) 
Part 2) 
Step-by-step explanation:
Step 1
Find the length of MD
we know that
The incenter is the intersection of the angle bisectors of the three vertices of the triangle. Is the point forming the origin of a circle inscribed inside the triangle
so
In this problem
------> is the radius of a circle inscribed inside the triangle
we have that
therefore
Step 2
Find the length of DC
we know that
In the right triangle MDC
Applying the Pythagoras theorem
we have
substitute
Answer:
That would be sina.
Step-by-step explanation:
sin(a+b) = sinacosb + cosasinb
sin(a-b) = sinacosb - cosasinb
Adding we get sin(a+b) + sin(a-b) = 2sinaccosb
so sinacosb = 1/2sin(a+b) + sin(a-b)
