All categories

3 years ago

In the voting for mayor, Candidate Russell received 0.8 of the votes. What is 0.8 written as a percent?

2 answers:

3 0

.8 is 80% this is because .8 can be written as a fraction 80/100 this is 80% another way we could have found this is by multiplying .8 times 100 because that is our denominator.

Kitty [74]3 years ago

3 0

It is written as 80% but can also be written as
Fractions 4/5, 8/10
Ratios 8:10, 4:5

You might be interested in

Experian would like to test the hypothesis that the average credit score for an adult in Virginia is different from the average

aliya0001 [1]

Answer:

a. We fail to reject the hypothesis that the average credit score for an adult in Virginia is different from the average credit score for an adult in North Carolina at the significance level of 0.05.

b. The 95% confidence interval for the true difference of means is -2.2468 and 36.2468. There is a probability of 95% that the true difference of means $\mu_{1}-\mu_{2}$ is between -2.2468 and 36.2468. This confidence interval contains the number 0, this is consistent with the results we got in a. Because we fail to reject the hypothesis that the average credit score for an adult in Virginia is different from the average credit score for an adult in North Carolina at the significance level of 0.05.

Step-by-step explanation:

Let $\mu_{1}-\mu_{2}$ be the true difference between the average credit score for an adult in Virginia and the average credit score for an adult in North Carolina. We have the large sample sizes $n_{1} = 40$ and $n_{2} = 35$ , the unbiased point estimate for $\mu_{1}-\mu_{2}$ is $\bar{x}_{1} - \bar{x}_{2}$ , i.e., 699-682 = 17.

The standard error is given by $\sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}$ , i.e.,

$\sqrt{\frac{(44)^{2}}{40}+\frac{(41)^{2}}{35}}$ = 9.8198.

a. We want to test $H_{0}: \mu_{1}-\mu_{2} = 0$ vs $H_{1}: \mu_{1}-\mu_{2} \neq 0$ (two-tailed alternative). The rejection region is given by RR = {z | z < -1.96 or z > 1.96} where -1.96 and 1.96 are the 2.5th and 97.5th quantiles of the standard normal distribution respectively. The test statistic is $Z = \frac{\bar{x}_{1} - \bar{x}_{2}-0}{\sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}}$ and the observed value is $z_{0} = \frac{17}{9.8198} = 1.7312$ . Because 1.7312 does not fall inside RR, we fail to reject the null hypothesis.

b. The endpoints for a 95% confidence interval for $\mu_{1}-\mu_{2}$ is given by $17\pm (z_{0.05/2})9.8198$ , i.e., $17\pm (z_{0.025})9.8198$ where $z_{0.025}$ is the 2.5th quantile of the standard normal distribution, i.e., -1.96, so, we have 17-(1.96)(9.8198) and 17+(1.96)(9.8198), i.e., -2.2468 and 36.2468. There is a probability of 95% that the true difference of means $\mu_{1}-\mu_{2}$ is between -2.2468 and 36.2468. This confidence interval contains the number 0, this is consistent with the results we got in a. Because we fail to reject the hypothesis that the average credit score for an adult in Virginia is different from the average credit score for an adult in North Carolina at the significance level of 0.05.

3 0

4 years ago

PLEASE HURRY

jek_recluse [69]

C is the answer i believe

5 0

3 years ago

Read 2 more answers

57 POINTS!!!!!!! PLEASE HELP MEE. ALSO DUEE RIGHT NOW

sweet [91]

Answer:

1. 2

2. 5.2

3. (c * 2) - 3= a

4. ($85 + $35 * h)

Step-by-step explanation:

1. |4−2| (simplified)

= |2|

2. 2a^2 = 5.2

(22)(1.3)

=(4)(1.3)

=5.2

(2.6 - (2*1.3))=

5.2 - (2.6 - 2.6) = 5.2

3. (c * 2) - 3= a

4. ($85 + $35 * h)

5 0

3 years ago

Paula purchase 3 dvd and 7 cds and spent between 90 and 100. Each dvd costs the same amount the price of cd is 10 select all amo

sveticcg [70]

The options aren't given, however, the range of amount spent could be calculated

Answer:

Kindly check explanation

Step-by-step explanation:

Paula purchase 3 dvd and 7 cds and spent between 90 and 100. Each dvd costs the same amount the price of cd is 10 select all amounts that could be the price of the dvd

Given that :

DVD costs the same amount

Number of DVD's = 3

Cost of cds = 10

Number of cds = 7

Total cost of cd's = 10 * 7 = 70

Let the price of DVD = x

Total amount spent = 90 - 100

Lowest price of DVD :

(amount spent - price of cd) / number of dvd

(90 - 70) / 3 = 20 /3 = 6.667

Highest price :

(100 - 70) / 3 = 30 / 3 = 10

Hence the pice of each DVD will range between /

6.6666 and 10.

Hence, prices listed within the range above are possible.

3 0

3 years ago

G(x) = 4x + 2

mojhsa [17]

Answer:

$4x \times 2x + 4x \times 5 + 2 \times 2x + 2 \times 5 = 8x {}^{2} + 24x + 10$

6 0

3 years ago