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Veronika [31]
3 years ago
14

WHERE DOES THE PYTHAGOREAN IDENTITY SIN2 Θ + COS2 Θ = 1 COME FROM? HOW WOULD YOU USE IT TO FIND THE SINE COSINE AND TANGENT VALU

ES OF THE ANGLE?
Mathematics
2 answers:
Allushta [10]3 years ago
7 0

Imagine a trigonometric circle with radius equal to 1.

We can say that the opposite side of the angle generated by the origin is equal to sen Ф and the adjacent equal to cos Ф


With this we can say that:


h² = c² + c²


If r = 1, then h = 1


1² = cos² + sen²

1 = cos² Ф + sen² Ф


You can use this equation a lot of times because it's the fundamental trigonometric relation
, so, when you something like:


sen Ф = cos Ф + 1


you can take from sen² Ф + cos² Ф = 1 that sen = \sqrt{1 - cos^2} and then resolve.

lesya [120]3 years ago
4 0

Suppose we have a right- angled triangle with theta has one of the angles ( not 90 degrees) and hypotenuse c , opposite side a and adjacent side b.

then sin α = a/c giving a = c sin α .............(1)

and cos α = b/c giving b = c cos α...............(2)

by Pythagoras theorem:-

a^2 + b^2 = c^2 and from equations (1) and (2):-

a^2 + b^2 = c^2 sin^2 α + c^2 cos^2 α

a^2 + b^2 = c^2 ( sin^2 α + cos^2 α)

Comparing this equation with the Pythagoras equation sin^2 α + cos^2 α must equal 1.

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rjkz [21]

The answer is number two.

5 0
3 years ago
A lot of 100 semiconductor chips contains 15 that are defective. three chips are selected at random from the lot without replace
Alex787 [66]
D=event that chip selected is defective
d=event that chip selected is NOT defective

Four possible scenarios for the first two selections:
P(DDD)=15/100*14/99*13/98=13/4620
P(DdD)=15/100*85/99*14/98=17/924
P(dDD)=85/100*15/99*14/99=17/924
P(ddD)=85/100*84/99*15/98=17/154

Probability of third selection being defective is the sum of all cases,
P(XXD)=P(DDD)+P(DdD)+P(dDD)+P(ddD)
=3/20


5 0
3 years ago
If A+B+C=<img src="https://tex.z-dn.net/?f=%5Cpi" id="TexFormula1" title="\pi" alt="\pi" align="absmiddle" class="latex-formula"
seraphim [82]

Answer:

a + b + c = \pi \\  =  > c=  \pi - a - b \\  <  =  >  \tan(c)  =  \tan(\pi - a - b)  =  -\tan(a + b)

Step-by-step explanation:

we have:

\tan(a)  +  \tan(b)  +  \tan(c)  \\  =  \tan(a)  +  \tan(b)  -  \tan(a + b)  \\  =  \tan( a)  +  \tan(b)  -  \frac{ \tan(a) +  \tan(b)  }{1 -  \tan(a)  \tan(b) }  \\  =  \frac{ ( \tan(a) +  \tan(b)  ) \tan(a) \tan(b)  }{ \tan(a) \tan(b)  - 1 } (1)

we also have:

\tan(a)  \tan(b)  \tan(c)  \\  =  -  \tan(a)  \tan(b)  \tan(a + b)  \\  =  \frac{ -(\tan( a  )   + \tan(b) ) \tan(a)  \tan(b) }{1 -  \tan(a)  \tan(b) }  \\  =  \frac{( \tan(a)  +  \tan(b)) \tan(a)   \tan(b) }{ \tan(a) \tan(b)  - 1 } (2)

from (1)(2) => proven

5 0
3 years ago
74.94×103= <br> because the number 10³ has ?<br> zeros when it is written without an exponent.
horsena [70]

Answer:

74940, three

Step-by-step explanation:

74.94 × 10³

74.94 × 1000

74940

6 0
3 years ago
Can someone help? I suck at this
Usimov [2.4K]

Answer:

23 cm squared

Step-by-step explanation:

Split the shape into two shapes.

<u>Shape one:</u>

5 x 3 = 15 cm squared

<u>Shape two:</u>

7 - 3 = 4 (length of a side of the second shape)

4 x 2 = 8 cm squared

15 + 8 = 23 cm squared

4 0
3 years ago
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