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erastovalidia [21]
4 years ago
12

A doctor can prescribe one of two drugs to treat a certain disease. Drug A will cure 75% of the cases but has unwanted side effe

cts in 40% of the cases. Drug B will cure 50% of the cases and has unwanted side effects in 30% of cases. 60 patients are given drug A and 80 patients are given drug B. How many patients would you expect to experience unwanted side effects?
Mathematics
2 answers:
iVinArrow [24]4 years ago
4 0
<span>60 patients x 40 % = 24 and 80 patients x 30 % = 24. So 24 + 24 = 48</span>
Phoenix [80]4 years ago
3 0

The total number of patients experienced unwanted side effects is 48

<u><em>Explanation</em></u>

60 patients are given drug A and drug A has unwanted side effects in 40% of the cases.

So, the number of patients experienced side effects for drug A = 40% of 60 =(0.40*60)= 24

Now 80 patients are given drug B and it has side effects in 30% of the cases.

So, the number of patients experienced side effects for drug B = 30% of 80 =(0.30*80)= 24

So, the total number of patients experienced unwanted side effects = 24+24 =48

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Answer:

Expected time is 15 hours for him to get to safety.

Step-by-step explanation:

We define X as the time that this miner would get to safety.

We define Y as the door he chooses initially.

P(Y= 1) = P(Y=2)=P(Y=3) = 1/3

We have E[X|Y=1] = 3

E[X|Y] = 5 hours + E[X}

E[X|Y] = 7 hours + E[X]

Then we have

E[X] = 1/3(3 + 5 + E[X] + 7 + E[X])

We cross multiply

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E[X] = 15

So the time it would take to get him to safety is 15 hours

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3 years ago
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Answer:

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3 0
4 years ago
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Pani-rosa [81]
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3 0
4 years ago
4x+5y=-35? A) y=-4/5x-7 B)y=1/5x-7 C)y=-7x+1/5 D)y=7x+1/5
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5 0
4 years ago
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