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3 years ago

Which of the following polynomial equations are valid identities?

Mathematics

1 answer:

Margarita [4]3 years ago

7 0

Only a is valid because
<span>(a + b)(2a + 1) = a(2a + 2b +1)</span>

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The TV weather forecaster announces that one location has a 75% chance of sleet tomorrow and a 5% chance of snow. What is the pr

alexandr1967 [171]

Answer:

80%

Step-by-step explanation:

4 0

3 years ago

4(x-2)+2(x+1)<br><br> Help plz

enyata [817]

Answer:

6(x-1)

Step-by-step explanation:

Open brackets.

4x-8+2x+2

Solve and simplify

6x-6

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6(x-1)

8 0

3 years ago

Which equation has a y intercept of 2 and a slope of 1/2?

jek_recluse [69]

Y = mx + b where m = slope and b is y intercept

<span>y intercept of 2 and a slope of 1/2 then
y = 1/2 x + 2

answer
</span><span>B.y = 1/2 x + 2</span>

8 0

3 years ago

I need the answer ASAP :( really struggling

pashok25 [27]

<h3>Answer: Choice A $-4 \le x \le -2$ </h3>

Explanation:

Ask yourself this: "When is the graph completely horizontally flat?" The answer to this question is when x is between -4 and -2. This is where the graph is constant. All other intervals are either increasing or decreasing.

Saying "The graph is constant" basically means "constant rate of change", which is another way of saying that the graph isn't changing. Constant means it stays the same.

So this is why the answer is $-4 \le x \le -2$

Note how only choice A has both endpoints in the negative region, so it is a quick way to spot the answer.

3 0

3 years ago

Find the inverse of the following function:

tigry1 [53]

First, we are going to find the inverse function of $f(x)$ by replacing $f(x)$ with $y$ , and then, interchanging $x$ and $y$ and solving for $x$ :
$y=-2 \sqrt{3x-1} -5$
$x=-2 \sqrt{3y-1} -5$
$-2 \sqrt{3y-1} =x+5$
$\sqrt{3y-1} = \frac{x+5}{-2}$
$3y-1=( \frac{x+5}{-2} )^{2}$
$3y=( \frac{x+5}{-2} )^{2} +1$
$y= \frac{( \frac{x+5}{-2})^{2}+1 }{3}$

Next we are going to evaluate our inverse function at $x= \frac{1}{3}$ :
$y= \frac{( \frac{ \frac{1}{3}+5 }{-2})^{2}+1 }{3}$
$y= \frac{( \frac{ \frac{16}{3} }{-2})^{2}+1 }{3}$
$y= \frac{(- \frac{8}{3})^{2}+1 }{3}$
$y= \frac{ \frac{64}{9}+1 }{3}$
$y= \frac{ \frac{73}{9} }{3}$
$y= \frac{73}{27}$

We can conclude that the inverse function of $f(x)=-2 \sqrt{3x-1} -5$ when $x= \frac{1}{3}$ is $\frac{73}{27}$

5 0

3 years ago