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Law Incorporation [45]

3 years ago

5

Darnell rented a moving truck the weight of the empty truck was 7860 pounds when Darnell fill the truck with his items it weighe

d 6 tons what was the weight in pounds of the items that are now placed in the truck

1 answer:

Diano4ka-milaya [45]3 years ago

4 0

A ton weighs 2000 pounds, so if you were to take 6 tons, it will be 12000 pounds.

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Who can access your credit report?

Maksim231197 [3]

This answer would be B

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3 years ago

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Which statements are true regarding undefinable terms in geometry?All that apply.

valentinak56 [21]

D.A plane consist of an infinite set of lines.

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3 years ago

What is the measure of angle b°?

Tasya [4]

Answer:

b = 110°

Step-by-step explanation:

The sum of angles in a trapezoid is 360°

Summing the angles we get:

65°+55°+130°=250°

Then subtracting this value from 360° we get:

360°-250°=110°

Final answer of 110°

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2 years ago

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I need help with this, please! I need to solve this using inverse operation to isolate the variable.

Otrada [13]

Since the inverse property of subtraction is addition, wouldn’t you add n on both sides so then the value of n=0?

5 0

2 years ago

EXPLAIN why we placed the value of x= 4/3( the minimum value) into the equ of gradient(dy/dx) [in the answer, marking scheme att

aliina [53]

$y=x(x-2)^2$
$\implies y'=(x-2)^2+2x(x-2)=3x^2-8x+4=(3x-2)(x-2)=0$
$\implies x=\dfrac23,x=2$

are the critical points, and judging by the picture alone, you must have $b=\dfrac23$ and $a=2$ . (You might want to verify with the derivative test in case that's expected.)

Then the shaded region has area

$\displaystyle\int_0^2x(x-2)^2\,\mathrm dx=\dfrac43$

I'll leave the details to you.

Now, for part (iv), you're asked to find the minimum of $\dfrac{\mathrm dy}{\mathrm dx}=y'$ , which entails first finding the second derivative:

$y'=3x^2-8x+4$
$\implies y''=6x-8$

setting equal to 0 and finding the critical point:

$6x-8=0\implies x=\dfrac86=\dfrac43$

This is to say the minimum value of $\dfrac{\mathrm dy}{\mathrm dx}$ *occurs when $x=\dfrac43$ *, but this is not necessarily the same as saying that $\dfrac43$ is the actual minimum value.

The minimum value of $\dfrac{\mathrm dy}{\mathrm dx}$ is obtained by evaluating the derivative at this critical point:

$m=\dfrac{\mathrm dy}{\mathrm dx}\bigg|_{x=4/3}=3\left(\dfrac43\right)^2-8\left(\dfrac43\right)+4=-\dfrac43$

4 0

4 years ago