1. Construct a circle of arbitrary radius (r₁) with center at point P (blue circle)
2. Mark the points of intersection of the circle with the line AB (points E and D)
3. Construct two circles of identical radii (r₂) with centers at points E and D (green and red circles). Notice: r₂ > r₁
4. Draw a segment through the intersection points of the green and red circles.
Answer:
Step-by-step explanation:
I think your question missed key information, allow me to add in and hope it will fit the orginal one
<em>For the graph below, what should the domain be so that the function is at least 200? graph of y equals minus 2 times the square of x plus 30 times x plus 200
</em>
My answer:
Given the above information, we have:
To make the function is at least 200, it means that:
≥ 200
<=> 
≥ 0
<=> x(-2x+30) ≥ 0
This is the product of two numbers hence would be positive only if either both are positive or both are negative
x ≥ 0 and (-2x+30) ≥ 0
<=> 0 ≤ x ≤ 15
Then we get
This is inconsistent as a value cannot be less than 0 and greater than 15
=> our correct answer is
Hope it will find you well.
Answer:
4
2
one-half
Step-by-step explanation:
Hope this helps!! :)
Answer:
When an exponent is 1, the base remains the same. a 1 = a . When an exponent is 0, the result of the exponentiation of any base will always be 1, although some debate surrounds 0 0 being 1 or undefined. For many applications, defining 0 0 as 1 is convenient.. a 0 = 1 . Shown below is an example of an argument for a 0 =1 using one of the previously mentioned exponent laws.
Step-by-step explanation:
Um I can't answer without an image
