For simple integer factors as this one has, you want to find two values for the quadratic in the form ax^2+bx+c. Let the two values be j and k. These two values must satisfy two conditions.
jk=ac=10 and j+k=b=11, so j and k must be 1 and 10.
Now replace bx with jx and kx...
2x^2+x+10x+5 now factor 1st and 2nd pair of terms.
x(2x+1)+5(2x+1)
(x+5)(2x+1)
Answer:
B. 175 square cm
Step-by-step explanation:
Area of the figure = Area of parallelogram + Area of square + Area of triangle
Area of parallelogram = (base x height)
= (14 x 5)
= 70 
Area of square = (length x length)
= (7 x 7)
= 49 
Area of triangle = (
base x height)
= (
x 16 x 7)
= 56 
Area of the figure = 70+ 49 + 56
= 175
The area of the figure is 175
.
Answer:
D: 7
Step-by-step explanation:
1.75 (7) + 4.50
12.25 + 4.50
= 16.75
16.75 < 20
The answer to that problem si 6-25+2x
It can be anything. If you are talking about math