Consider the chemical reaction represented below

How do purple stem plants use there energy

tatuchka [14]

Purple stem plants can be formed by genetics, they use their energy slightly different from other plants, they use less energy, but that may also be because of bad nutrition, and because they may be hungry for nutrients.

5 0

2 years ago

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The mass of a deuterium nucleus 21H is less than its components masses. Calculate the mass defect.________ amu

Inessa [10]

Answer:

The mass defect of a deuterium nucleus is 0.001848 amu.

Explanation:

The deuterium is:

$^{A}_{Z}X \rightarrow ^{2}_{1}H$

The mass defect can be calculated by using the following equation:

$\Delta m = [Zm_{p} + (A - Z)m_{n}] - m_{a}$

Where:

Z: is the number of protons = 1

A: is the mass number = 2

$m_{p}$ : is the proton's mass = 1.00728 amu

$m_{n}$ : is the neutron's mass = 1.00867 amu

$m_{a}$ : is the mass of deuterium = 2.01410178 amu

Then, the mass defect is:

$\Delta m = [1.00728 amu + (2- 1)1.00867 amu] - 2.01410178 amu = 0.001848 amu$

Therefore, the mass defect of a deuterium nucleus is 0.001848 amu.

I hope it helps you!

5 0

2 years ago

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Most modern medications are given in doses of milligrams. Thyroid medications, however, are typically given in doses of microgra

leonid [27]

Answer:

0.125 mg

Explanation:

<em>The correct answer would be 0.125 mg</em>

<u>According to the conversion factor, one milligram of a sample is equivalent to one thousand micrograms of the same sample.</u>

milligram = $10^{-3}$

microgram = $10^{-6}$

Hence,

1 milligram = 1000 micrograms or 1 microgram = $10^{-3}$ milligram

Therefore, 125 micrograms will be:

125/1000 = 0.125 milligram

4 0

3 years ago

Please help im really stressed and doing 2 tests at the same time

DanielleElmas [232]

The answer is A, good luck

7 0

3 years ago

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A 1.450 g sample of an unknown organic compound , X, is dissolved in 15.0 g of toluene

muminat

Answer:

Molecular weight of the compound = 372.13 g/mol

Explanation:

Depression in freezing point is related with molality of the solution as:

$\Delta T_f = K_f \times m$

Where,

$\Delta T_f$ = Depression in freezing point

$K_f$ = Molal depression constant

m = Molality

$\Delta T_f = K_f \times m$

$1.33 = 5.12 \times m$

m = 0.26

Molality = $\frac{Moles\ of\ solute}{Mass\ of\ solvent\ in\ kg}$

Mass of solvent (toluene) = 15.0 g = 0.015 kg

$0.26 = \frac{Mole\ of\ compound}{0.015}$

Moles of compound = 0.015 × 0.26 = 0.00389 mol

$Mol = \frac{Mass\ in\ g}{Molecular\ weight}$

Mass of the compound = 1.450 g

$Molecular\ weight = \frac{Mass\ in\ g}{Moles}$

Molecular weight = $\frac{1.450}{0.00389} = 372.13\ g/mol$

4 0

2 years ago