Answer:- Chlorine(Cl)
Explanations:- Electron affinity is the amount of energy released when an electron is added to an element in it's gaseous state. Electron affinity increases in a period on going left to right as the size of the element decreases and it's effective nuclear charge increases and this facilitate an element to accept the electron.
The elements mentioned here in the question belongs to the same group and out of these, chlorine is on the right most side and so it is correct choice.
Hence, Chlorine(Cl), because it is a halogen with a high effective nuclear charge is the correct choice.
Answer:
There will be produced 3.5 moles of oxygen (O2)
Explanation:
Step 1: Data given
Number of moles Mercury (II) oxide (HgO) = 7 moles
Step 2: The balanced equation
2HgO → O2 + 2Hg
Step 3: Calculate number of moles of O2
For 2 moles of Mercury (II) oxide (HgO) we produce 1 mol of O2 and 2 moles of Hg
For 7 moles of Mercury (II) oxide (HgO) we'll have 7/2 = 3.5 moles of O2
There will be produced 3.5 moles of oxygen (O2)
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Answer:
This is a conversion factor
Coulomb's law mathematically is:
F = kQ₁Q₂/r²
we integrate this with respect to distance to obtain the expression for energy:
E = kQ₁Q₂/r; where k is the Coulomb's constant = 9 x 10⁹; Q are the charges, r is the seperation
Charge on proton = charge on electron = 1.6 x 10⁻¹⁹ C
E = (9 x 10⁹ x 1.6 x 10⁻¹⁹ x 1.6 x 10⁻¹⁹) / (185 x 10⁻¹²)
E = 1.24 x 10⁻¹⁸ Joules per proton/electron pair
Number of pairs in one mole = 6.02 x 10²³
Energy = 6.02 x 10²³ x 1.24 x 10⁻¹⁸
= 746.5 kJ
