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Bezzdna [24]
3 years ago
5

What is the quartile three of the following set of data? 202, 199, 223, 198, 223, 223, 301, 199, 200, 212, 215

Mathematics
1 answer:
Elenna [48]3 years ago
6 0

Answer:

Q3 = 223

Step-by-step explanation:

The given data is:

198, 199, 199, 200, 202, 212, 215, 223, 223, 223, 301

Let us use the quartile formula for the Quartile 3 (Q3):

Q_3 = (N + 1) * \frac{3}{4}

N = number of data points= 11

Therefore:

Q_3 = (11 + 1)  * \frac{3}{4} \\\\Q_3 = 12 * 3/4\\\\Q_3 = 9

Therefore, the upper quartile (Q3) is the 9th data point i.e. 223

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Which of the following is a solution to the equation −25x = 10?
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Answer: x=-0.4

Step-by-step explanation:

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3 years ago
Anyone know this ???
mr Goodwill [35]

Answer:

B and C

Step-by-step explanation:

The 2 smallest numbers have to add up to be bigger then the largest number in the set for it to be a triangle! I hope this helps!

7 0
2 years ago
the mean of a set of numbers is 120. if one number is increased by 300, the mean increases to 135. how many numbers are in the s
stiks02 [169]

There are 20 numbers in the set.

Given,

Set of numbers is 120

one number is increased by 300

and, mean increases to 135.

To find the how many numbers are in the set?

Now, According to the question:

Let the number of numbers be 'n'

Then, (sum of numbers)/n = 120

or, old sum = 120n

if one number is increased by 300, the new sum = (old sum + 300)

Then, (new sum)/ n= 135

or new sum = 135n = old sum + 300 = 120n + 300

The equation will  be:

135n = 120n + 300

15n = 300

n = 20

Hence, There are 20 numbers in the set.

In the question:

The mean of a set of numbers is 120. if one number is increased by 300, the mean increases to 135.

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3 0
1 year ago
What’s the answer to this?
nexus9112 [7]

the answer is 5.10729613...

4 0
3 years ago
Read 2 more answers
Line JK passes through points J(-4,-5) and K(-6, 3). If the equation of the line is written in slope-intercept form, y = mx + b,
Scilla [17]

Answer:

Line JK passes through points J(-4,-5) and K(-6, 3).

Line JK has form of y = mx + b

=> -5 = -4m + b

=>  3 = -6m + b

Subtract 2nd equation from 1st equation:

=> -8 = 2m

=> m = -4

Substitute back m = -4 into 1st equation:

=> -5 = -4(-4) + b

=> b = -21

Hope this helps!

:)

6 0
3 years ago
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