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Crank
3 years ago
15

Question in attachment

Mathematics
2 answers:
Lerok [7]3 years ago
7 0

Answer:

cos(x)=-\frac{\sqrt{3} }{2}

sin(x)=\frac{1}{2}

tan(x)=-\frac{1}{\sqrt{3} }

csc(x)=2

sec(x)=-\frac{2}{\sqrt{3}}

cot(x)=-\sqrt{3}

Step-by-step explanation:

(I'll just use x for ease of writing)

We have the trig equation cos(x)=-\frac{\sqrt{3} }{2}, and we know that its terminal side is in the 2nd quadrant. By using a unit circle, we can determine that the angle is \frac{5\pi}{6} which has an ordered pair of (-\frac{\sqrt{3} }{2},\frac{1}{2} )

sin(x)=y, so sin(x)=\frac{1}{2}

tan(x)=\frac{y}{x}, so tan(x)=\frac{\frac{1}{2} }{-\frac{\sqrt{3} }{2} }=-\frac{1}{\sqrt{3} }

Now that we have sin, cos, and tan, we can just take the reciprocal of each of these to get our answers for csc, sec, and cot.

csc(x)=\frac{1}{sin(x)}, so csc(x)=2

sec(x)=\frac{1}{cos(x)}, so sec(x)=-\frac{2}{\sqrt{3}}

cot(x)=\frac{1}{tan(x)}, so cot(x)=-\sqrt{3}

Volgvan3 years ago
3 0

Step-by-step explanation:

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