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allochka39001 [22]
3 years ago
13

The data below represents the ages of the first ten people in line at the movie theater.

Mathematics
1 answer:
tresset_1 [31]3 years ago
5 0
It could be a box plot or a Histogram
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Ok so if had rap song like da baby sold two songs and each we $5 million for example his lyric
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Which digit in 2,385,679 has a value that is greater than 10 times the value of the first digit to its right?
guajiro [1.7K]

Answer:

Hey there!

8 is the correct answer.

It is 16 times greater than the digit to it's right.

Let me know if this helps :)

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A bird is attempting to fly northeast at a constant speed, but a wind blowing southward at 5 miles per
guajiro [1.7K]

Answer:

The value is v_b  =  9.89 \  miles /hour

Step-by-step explanation:

From the question we are told that

The velocity of the wind southward is v  =  5 j \  miles / hour

The resultant velocity of the bird with the with wind is V= \sqrt{53}

Generally for an object moving in the northwest direction the angle with the horizontal is 45°

Generally the velocity of the bird in the along the x -axis is

V_x= v_b cos 45^o i

Generally the velocity of the bird in the along the y -axis is

V_y=(v_b sin 45^o - 5)j

Here v_b is the velocity of the bird without the wind

Generally the resultant velocity of the bird with the with wind is mathematically represented as

V  =  \sqrt{V_x^2 + V_y^2 }

=> \sqrt{53}  =  \sqrt{(v_b cos 45^o)^2 + (v_b sin 45^o - 5)^2 }

Generally

sin 45^o = \frac{1}{\sqrt{2} }

and

cos 45^o = \frac{1}{\sqrt{2} }

So

\sqrt{53}  =  \sqrt{(v_b* (\frac{1}{\sqrt{2} ))^2 + ([v_b * (\frac{1}{\sqrt{2} ) ]- 5)^2 }

=> 53 =  \frac{1}{2} v_b^2  +  \frac{1}{2} v_b^2 + 5^2 -2*5 * \frac{1}{\sqrt{2} } v_b

=> 53 =  v_b^2 + 25 - 5 \sqrt{2} v_b

=> v_b^2 - 5 \sqrt{2} v_b -28 = 0

Solving the above quadratic equation using quadratic formula we obtain that

v_b  =  9.89 \  miles /hour

The other value is negative so we do not make use of it because we know that the bird is moving in the positive x and y axis

7 0
3 years ago
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