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3 years ago

12

There arre a total of 82 students in robotics club and the science club the science club has 6 fewer students than the robotics

club. How many students are in the science club?

2 answers:

serious [3.7K]3 years ago

8 0

Answer:

88

Step-by-step explanation:

You are just adding 82+6=88

Novosadov [1.4K]3 years ago

4 0

There would be 35 students in the science club

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Express the equation x = 10 and y = -3 as a linear equation in two variables

34kurt

Answer:

For x = 10:

$x + 0y - 10 = 0$

For y = - 3:

$0x + y + 3 = 0$

Step-by-step Explanation:

Before we start let's recall the formula for the linear equations.

$ax + bx = c$

So first let's solve for x=10:

$x = 10$

Move 10 to the other side.

$x - 10 = 0$

As there is no y given we will simply write 0y.

$x + 0y - 10= 0$

Now let's solve for y=-3:

$y = - 3$

Move -3 to the other side.

$y + 3 = 0$

As there is no x given we will simply write 0x.

$0x + y + 3 = 0$

If this answer helped you, give this answer a heart, rate it and if you could then please mark it brainliest. Thanks!

8 0

1 year ago

Anne, Barry, and Cathy enter a coffee shop. Anne orders two coffees, one juice, and two doughnuts and pays $7.50. Barry orders o

Evgesh-ka [11]

Answer:

Coffee = $2.00

Juice = $1.50

Doughnut = $1.00

Step-by-step explanation:

Given

Let:

$c = coffee\\ j= juice\\ d = doughnut$

So, we have:

Anna

$2c + j + 2d = 7.50$

Barry

$c + 3d = 5.00$

Cathy

$3c + j + 4d = 11.50$

Required

The price of each

We have:

$2c + j + 2d = 7.50$

$c + 3d = 5.00$

$3c + j + 4d = 11.50$

Make c the subject in: $c + 3d = 5.00$

$c = 5.00 - 3d$

Substitute $c = 5.00 - 3d$ in $2c + j + 2d = 7.50$ and $3c + j + 4d = 11.50$

$2c + j + 2d = 7.50$

$2[5.00 - 3d] + j + 2d = 7.50$

$10.00 - 6d+ j + 2d = 7.50$

Make j the subject

$j = 7.50 - 10.0 +6d - 2d$

$j = -2.50 +4d$

$3c + j + 4d = 11.50$

$3[5.00 - 3d] + j + 4d = 11.50$

$15.00 - 9d + j + 4d = 11.50$

Make j the subject

$j = 11.50 - 15.00 + 9d -4d$

$j = -3.50 + 5d$

So, we have:

$j = -3.50 + 5d$ and $j = -2.50 +4d$

Equate both values of j

$-3.50 + 5d = -2.50 + 4d$

Collect like terms

$5d - 4d = 3.50 -2.50$

$d = 1.00$

Substitute $d = 1.00$ in $j = -3.50 + 5d$

$j = -3.50 + 5d$

$j = -3.50 + 5 * 1.00$

$j = -3.50 + 5.00$

$j = 1.50$

To solve for c, we substitute $d = 1.00$ in $c + 3d = 5.00$

$c + 3 * 1.00 =5.00$

$c + 3.00 =5.00$

Solve for c

$c =- 3.00 +5.00$

$c =2.00$

7 0

2 years ago

(WORTH 95 POINTS) PLEASE HELP I CANNOT FIGURE IT OUT AND ITS SUPPOSED TO BE TURNED IN ALREADY!

yanalaym [24]

Hope this helped :3

:)

5 0

3 years ago

Jenny earned a 77 on her most recent test. Jenny’s score is no less than 5 points greater than 4/5 of Terrance’s score. If t rep

hram777 [196]

77 $\geq$ 5 + 4/5t

7 0

3 years ago

Read 2 more answers

What Is the solution to the system of equations? Y=-3x-2<br> 5x+2y=15

snow_tiger [21]

Answer:

x,y=-19,55

Step-by-step explanation:

plug in y.

5x+2(-3x-2)=15

5x-6x-4=15

-x=19

x=-19.

Plug in.

y=-3(-19)-2

y=55

correct is B.

Hope this helps :D

3 0

3 years ago