Question

If two dice are thrown whats si the probability that they will add to 9?A2/36B3/36C3/36D4/36

Answer 1

Answer:

D.$\frac{4}{36}$

Step-by-step explanation:

Solution,

Two dice are thrown.

So we have to find out the total number of outcomes.

$(1,1),\ (1,2),\ (1,3),\ (1,4),\ (1,5),\ (1,6)$

$(2,1),\ (2,2),\ (2,3),\ (2,4),\ (2,5),\ (2,6)$

$(3,1),\ (3,2),\ (3,3),\ (3,4),\ (3,5),\ (3,6)$

$(4,1),\ (4,2),\ (4,3),\ (4,4),\ (4,5),\ (4,6)$

$(5,1),\ (5,2),\ (5,3),\ (5,4),\ (5,5),\ (5,6)$

$(6,1),\ (6,2),\ (6,3),\ (6,4),\ (6,5),\ (6,6)$

The total number of outcomes = $36$

We have to find out the probability of outcomes that add up to 9.

So, Possible outcomes are;

$(3,6),\ (4,5),\ (5,4),\ (6,3)$

The total number of possible outcomes = $4$

Now, according to the formula of probability,

$P(E)=\frac{Total\ number\ of\ Possible\ outcomes}{Total\ Number\ of\ outcomes}$

$P(of\ add\ up\ to\ 9)=\frac{4}{36}$

Hence the correct option is D)4/36.