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spin [16.1K]
3 years ago
5

How many 5 mm square tiles do I need to cover an area of 930 cm square? The answer is 3720 tiles. How do you get that answer?

Mathematics
1 answer:
Igoryamba3 years ago
4 0

930 cm divided by 5mm

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The endpoints of a line segment graphed on a Cartesian coordinate system are (4, 1) and (-2, -4). What are the coordinates of th
Masja [62]
The midpoint of (x1,y1) and (x2,y2) is (\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

just average them


(4,1) and (-2,4)
the midpoint is  (\frac{4-2}{2},\frac{1-4}{2})=(\frac{2}{2},\frac{-3}{2})=(1,-1.5)
5 0
3 years ago
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Please show your work please
Nadusha1986 [10]
The correct answer is 4. 
5 0
3 years ago
In ΔUVW, w = 3 inches, ∠W=23° and ∠U=73°. Find the length of u, to the nearest 10th of an inch.
kirza4 [7]

Answer:

<h2>7.4inches</h2>

Step-by-step explanation:

Check the attachment for the diagram. Sine rule will be used to get the unknown side of the triangle.

According to the rule;

\frac{u}{sinU} =  \frac{v}{sinV} = \frac{w}{sinW}\\\frac{u}{sinU} = \frac{w}{sinW}

Given w = 3 in, ∠W=23° and ∠U=73°, on substituting into the equation above to get u we have;

\frac{u}{sin73^{0} } = \frac{3}{sin23^{0} }\\usin23^{0} = 3sin73^{0}\\u = \frac{3sin73^{0} }{sin23^{0} }\\u = \frac{2.87}{0.39} \\u = 7.358\\u = 7.4in

The length of u is 7.4inches to nearest 10th of an inch

6 0
3 years ago
The teachers sold 32 tickets this is 80% of the tickets given to the teachers how many tickets were given to the teachers
UkoKoshka [18]
You would give the teacher 40 tickets
6 0
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PLS HELP ASAP I WILL IVE BRAINLIST ANSWER!!!!!Leon verified that the side lengths 21, 28, 35 form a Pythagorean triple using thi
Juliette [100K]

Answer:

Leon is correct. (Option 1)

Step-by-step explanation:

Given that Leon verified that the side lengths 21, 28, 35 form a Pythagorean triple using this procedure.

Step 1: Find the greatest common factor of the given lengths: 7

Step 2: Divide the given lengths by the greatest common factor: 3, 4, 5

Step 3: Verify that the lengths found in step 2 form a Pythagorean triple.

we have to explain whether or not Leon is correct.

As, 3,4,5 forms a Pythagorean triplet i.e satisfies the Pythagoras theorem

Hypotenuse^2=Base^2+Perpendicular^2

⇒ 5^2=3^2+4^2

Let a, b, c forms a Pythagorean triplet

a^2+b^2=c^2

Multiplied by 4 on both sides

⇒ 4a^2+4b^2=4c^2

⇒ {2a}^2+{2b}^2={2c}^2

Hence, we say 4a, 4b and 4c also forms a Pythagorean triplet.

∴ multiplying every length of a Pythagorean triple by the same whole number results in a Pythagorean triple.

Hence, Leon is correct.

4 0
3 years ago
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