Question

Anyone please help me solve the area of parallelogram

Answer 1

Answer:

Therefore the area of parallelogram  is 32 cm².

Step-by-step explanation:

Given:

[] ABCD is a Parallelogram .........Given

AB = 4 cm = Base

BC = 10 cm

CE  = Height of Parallelogram  

To Find:

area of parallelogram  = ?

Solution:

In Right angle triangle BEC  by Pythagoras theorem we have

$(\textrm{Hypotenuse})^{2} = (\textrm{Shorter leg})^{2}+(\textrm{Longer leg})^{2}$

Substituting the values we get

$10^{2}=6^{2} +CE^{2} \\\\CE^{2}=100-36=64\\ \\\therefore CE = 8\ cm$

Which is the Height of Parallelogram

Now, area of parallelogram  given by

$\textrm{Area of Parallelogram} = Base\times Height$

Substituting the values we get

$\textrm{Area of Parallelogram} = 4\times 8=32$

$\textrm{Area of Parallelogram} = 32\ cm^{2}$

Therefore the area of parallelogram  is 32 cm².